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Paul [167]
3 years ago
12

A) The probability that you believe you will be in a car accident is 25%.

Mathematics
2 answers:
olga55 [171]3 years ago
8 0
The probability would be 20%
Alex777 [14]3 years ago
6 0

it would be 20% in a car accident

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Suppose your drawl card from the set of cards, record the letter, return the card to the set, and shuffle the cards. You can rep
Leto [7]

Answer:

The more the experiment is repeated the more the experimental probability should appear with the theoretical probability but they do not necessarily have to be the same.

Step-by-step explanation:

The theoretical probability would be the one calculated with the formula, the favorable cases divided by total cases and instead the experimental probability, is the quotient between the number of times the event occurred and the total number of events.

This means that the experimental probability, the more the experiment is carried out, the more it will appear to be the theoretical probability, because this is a trend, in this case, the more it is repeated, the more this trend is reached, but it is not necessarily the same.

3 0
3 years ago
If the price is 15 and the sales tax is 3%,what is the amount you will have to pay for tax?​
Gelneren [198K]

Answer:

$.45

Step-by-step explanation:

3% = .03

15 x .03 =

7 0
4 years ago
Which function below is the inverse of f(x)=x^2-36
Artyom0805 [142]

Answer:

+- square root of x+36

Step-by-step explanation:

f(x) = x^2 -36

y = x^2 -36

Exchange x and y

x = y^2 -36

Solve for y

Add 36 to each side

x+36 = y^2 -36+36

x+36 = y^2

Take the square root of each side

±sqrt(x+36) = y

±sqrt(x+36) = f^-1(x)

3 0
3 years ago
Find the value of 7x+2y when x=2 and y=-9
Nostrana [21]
Answer = -4

Step-by-Step Explanation:

Given: x = 2, y = -9

Therefore, substituting the values
= 7x + 2y
= 7(2) + 2(-9)
= 14 + -18
= 14 - 18
= -4
6 0
3 years ago
Read 2 more answers
#4 home do I find which one it is?
lina2011 [118]
\bf \begin{array}{lllll}
solutions&graphs&slopes\\
----&----&----\\
\textit{exactly one}&
\begin{array}{llll}
\textit{the two lines intersect}\\
\textit{at one point}
\end{array}&\textit{different slopes}\\\\
infinitely\quad many&
\begin{array}{llll}
\textit{the two lines coincide}\\
\textit{one is right on top}\\
\textit{ of the other}
\end{array}&
\begin{array}{llll}
\textit{equal slopes}\\
\textit{equal y-intercepts}
\end{array}
\end{array}

\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &
\begin{array}{llll}
\textit{equal slopes}\\
\textit{different y-intercepts}
\end{array}
\end{array}

for example, let's look at the first set

y+3x =5   or  y = -3x+ 5
and               y = -3x + 2
                    y =  m  + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution
8 0
4 years ago
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