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vovikov84 [41]
3 years ago
10

Ross and Ronnie are late for their favorite show . Ross walks around a rectangular park with dimensions of 150 ft by 215 ft. Ron

nie decides to cut across the park in a diagonal path. Who walks the shortest distance and by how much? *
Mathematics
1 answer:
sashaice [31]3 years ago
6 0

Answer:

Ronnie walked the shortest distance by (365 - 262.15 ) = 102.85 ft

Step-by-step explanation:

The image attached represent the rectangular park. In this case, the dimensions are;

AB = CD = 215 ft

AC = BD = 150 ft

Total distance walked by Ross = AB + BD = 215 + 150 = 365 ft

Distance walked by Ronnie = AD

∠ABD = right angle triangle, using pythagoras rules;

AD² = AB² + BD²

AD² = 215² + 150²

AD² = 68725

AD = √68725

AD = 262.15 ft

Distance walked by Ronnie = 262.15 ft

Ronnie walked the shortest distance by (365 - 262.15 ) = 102.85 ft

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4 0
3 years ago
Read 2 more answers
PQ is rotated 180 degrees clockwise about P. What are the coordinates of P' and Q'?
Salsk061 [2.6K]

The co ordinates of P' is (-7,-2) and Q' is (-16, -8)

<u><em>Explanation</em></u>

PQ is rotated 180 degrees clockwise about P. It means <u>P and P' are the same points</u>.

According to the graph, the coordinates of P is (-7, -2) and  Q is (2, 4)

When PQ is rotated 180 degrees clockwise about P, then <u>P or P' will be the mid-point of Q and Q' </u>

Suppose, the co ordinate of Q' is (x, y)

Now according to the mid-point formula, the coordinate of P or P' will be: (\frac{x+2}{2},\frac{y+4}{2}) , which is actually at (-7, -2)

Thus.....

\frac{x+2}{2}=-7\\ \\ x+2=-14\\ \\ x= -16\\ \\ and\\ \\ \frac{y+4}{2}= -2\\ \\ y+4= -4\\ \\ y= -8

So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)

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Answer:

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