Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
Step-by-step explanation:
Let x and y area the random variable that represents the heights of women and men.
Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.
i.e.

Since , 
Then, z-score corresponds to a woman 6 feet tall (i.e. x=72 inches).
[∵ 1 foot = 12 inches , 6 feet = 6(12)=72 inches]

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.
i.e.

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).
[∵ 1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
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This is very simple, you can use tally marks to find the amount of birthdays. Then divide it by 100. Good luck !
Answer:

Step-by-step explanation:
A direct variation equation has the following format:

Where k is a constant.
We know that y is 12 when x is -2. Thus, substitute:

Divide both sides by -2:

So, our direct variation equations is:

To find what x is when y equals -6, substitute in -6 for y:

Divide both sides by -6:

So, our answer is 1 :)