Answer:
The minimum percentage of noise level readings within 8 standard deviations of the mean is 98.44%.
Step-by-step explanation:
When we do not know the shape of the distribution, we use the Chebyshev's Theorem to find the minimum percentage of a measure within k standard deviations of the mean.
This percentage is:
![p = 1 - \frac{1}{k^{2}}](https://tex.z-dn.net/?f=p%20%3D%201%20-%20%5Cfrac%7B1%7D%7Bk%5E%7B2%7D%7D)
Within 8 standard deviations of the mean
This means that
. So
![p = 1 - \frac{1}{8^{2}} = 1 - \frac{1}{64} = \frac{64 - 1}{64} = \frac{63}{64} = 0.9844](https://tex.z-dn.net/?f=p%20%3D%201%20-%20%5Cfrac%7B1%7D%7B8%5E%7B2%7D%7D%20%3D%201%20-%20%5Cfrac%7B1%7D%7B64%7D%20%3D%20%5Cfrac%7B64%20-%201%7D%7B64%7D%20%3D%20%5Cfrac%7B63%7D%7B64%7D%20%3D%200.9844)
The minimum percentage of noise level readings within 8 standard deviations of the mean is 98.44%.
The value of expression is 7.
<h3>What is expression?</h3>
An expression is a combination of numbers, variables, functions (such as addition, subtraction, multiplication or division etc.)
Given:
![log 10^{7}](https://tex.z-dn.net/?f=log%2010%5E%7B7%7D)
Now, using property of log
a log b
So,
= 7 log 10
As log 10 = 1
= 7 (1)
= 7
Learn more expression here:
brainly.com/question/14083225
#SPJ1
Answer:
C. 364.4
E. 14
F. 21
G. 96°