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chubhunter [2.5K]
3 years ago
12

Consider this right triangle with given measures.

Mathematics
2 answers:
OlgaM077 [116]3 years ago
8 0

Answer:

\sqrt{39}

Step-by-step explanation:

I think the answer choices were supposed to be:

\sqrt{3} , \sqrt{6} , \sqrt{39} , \sqrt{89}

Pythagorean Theorem: a²+b²=c²

5²+b²=8²

25+b²=64

<em>Subtract 25 from both sides</em>

b²=39

<em>Square root both sides</em>

b=\sqrt{39}

Our answer is \sqrt{39}

pochemuha3 years ago
5 0

Answer:

\sqrt{39}

Step-by-step explanation:

just did it :)

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The correct answer is D. You can solve this by multiplying the values.

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Mr. Peters needs to build a rectangular pig pin 14 4/5 meters long and 5 1/5 meters wide
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Hope this us helpful

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2(n2 + 1) – 3(n2 – 3) + 3(2n2 – 2),<br> n=(1/4)
IceJOKER [234]

]Answer:

5\frac{5}{16}

Step-by-step explanation:

Substitute the value of the variable into the equation and simplify.

2(\frac{1}{4} ^{2} +1-3(\frac{1}{4} ^{2} -3)+3((2*\frac{1}{4}^{2}  )-2)

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3 years ago
Identify this conic section. 16y = x^2
kiruha [24]

ANSWER

A parabola.

EXPLANATION

The given conic is :

16y =  {x}^{2}

This can be rewritten as:

{x}^{2}  = 16y

{x}^{2}  = 4(4)y

This is a parabola with the vertex at the origin.

The foci is (0,4)

Therefore the given conic section is a parabola that has an axis of symmetry parallel to the y-axis.

7 0
3 years ago
Math:<br> Please help me I don’t understand and I need to do corrections.
GREYUIT [131]
So, you had done everything right so far (other than squaring the 2), but that was only half of the question.

to find the least common multiple, you need to first figure out what the prime factors have in common.
{2}^{2}  \times 3 \times 5 \\ and \\  {2}^{2}  \times  {3}^{2}  \times 5 \times 7
each have two twos. both have one 5, so we know our answer will look something like
{2}^{2}  \times 5 \times other \: stuff
now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.

one has one 3 and one has two, so we need two threes. now our equation is
{2}^{2}  \times {3}^{2}  \times 5 \times stuff

what's the only number we have to deal with? 7...

how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes
4 0
3 years ago
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