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3 years ago

Tabitha's mom is trying to decide between two plumber companies to fix her sink.

Mathematics

1 answer:

ohaa [14]3 years ago

5 0

Answer:

the amount due for 3 hours would be $52 + ($34/hr)(3 hrs) = $154

Step-by-step explanation:

Write two equations, one for the total cost payable to Water R Us and another to Clogs:

$52 + ($34/hr)t = $34 + ($40/hr)t, or

$18 = ($6/hr)t, which tells us that t = 3 (That's 3 hours).

At the time the charges from the two companies would be the same (3 hours into the job), the amount due for 3 hours would be

$52 + ($34/hr)(3 hrs) = $154

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Express the trig ratios as fractions in simplest terms.

Neporo4naja [7]

Answer:

See below

Step-by-step explanation:

$\cos M=\frac{adjacent}{hypotenuse}=\frac{56}{70}=\frac{4}{5}\\\\\sin L=\frac{opposite}{hypotenuse}=\frac{56}{70}=\frac{4}{5}$

Hence, both ratios are equal to each other

3 0

2 years ago

It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi

Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that $\mu = 35000, \sigma = 7000$

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

$Z = \frac{X - \mu}{\sigma}$

$-1.88 = \frac{X - 35000}{7000}$

$X - 35000 = -1.88*7000$

$X = 21840$

The designed life should be of 21,840 vehicle miles.

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