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Svetach [21]
3 years ago
8

What is the equation of the line with m = 6 that goes through the point (1, 4)?

Mathematics
2 answers:
Rzqust [24]3 years ago
8 0
Answer: B) y-4=6(x-1)

Substitute the point into each equation

A: y-4=6(x+1)

4-4=6(1+1)

4-4=6+6

0=12

This is false so it is not the answer

B: y-4=6(x-1)

4-4=6(1-1)

4-4=6-6

0=0

This is true so this is the answer, but I will continue solving just to check

C: y+4=6(x-1)

4+4=6(1-1)

4+4=6-6

8=0

This is false so it is not the answer

D: y+4=6(x+1)

4+4=6(1+1)

4+4=6+6

8=12
This is not true so it is not the answer

Your answer becomes b, the only true equation! Hope this helps comment below for more questions :)
tigry1 [53]3 years ago
6 0

Since it's a line we are talking about linear equation of a form

f(x)=mx+n

where m is slope and n is y-intercept.

Our particular line has a form of

f(x)=6x+n

So we are missing the y-intercept.

To find y-intercept n we insert the coordinates of point P(x,f(x))\to P(1,4) and solve for n

4=6\cdot1+n \\n=-2

So the final form of the line is

y=6x-2

Or as offered in the answers

y-4=6(x-1)

The answer is B.

Hope this helps.

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