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kodGreya [7K]
3 years ago
7

Translate the following verbal expression into an algebraic expression ... "The quotient of a number and four decreased by five"

​
Mathematics
1 answer:
irina1246 [14]3 years ago
4 0

Answer:

n/(4-5)

Step-by-step explanation:

A quotient of a number and... means that the number is being divided by whatever comes after. In this case the number that comes after is '4 decreased by 5', which is 4 - 5 as the -5 takes 5 away so it 'decreases it by 5'. Therefore is the expression is 'the quotient of a number and four decreased by five' then it is expressed in the following way (using n for number):

n/(4-5)

Hope this helped!

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What is the equation for a geometric sequence with a first term of 4 and a second term of −8?
mihalych1998 [28]
<h3>Answer:</h3>

a_n=4(-2)^{n-1}

<h3>Step-by-step explanation:</h3>

The common ratio is -8/4 = -2. The general formula for the n-th term is ...

... an = a1·r^(n-1) . . . . . . note the use of the caret (^) and parentheses

For r = -2 and a1 = 4, this becomes ...

... an = 4·(-2)^(n-1) . . . . approximately matches the 2nd selection

5 0
3 years ago
Let v = (1,-3) and w = (-2,6). Which of the following is true? Check all that apply.
luda_lava [24]
A) Vectors are usually given in the form (x , y), therefore the x-component of v is 1.

B) Similarly to point A), the y-component of w is 6

C) the magnitude of the vector v+w is given by:
√[(x₁ + x₂)² + (y₁ + y₂)²] = √[(1 + (-2))² + (-3 + 6)²] = √(1 + 9) =√10

D) Compute -2 · v = (-2·1 , -2·(-3)) = (-2 , 6) = w

Therefore options B) and D) are true.

3 0
3 years ago
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Find the x of =3(x+1)=12
kolezko [41]

Answer:

x = 3

Step-by-step explanation:

8 0
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The equation (x-6)^2/16 + (y+7)^2/4 = 1 represents an ellipse. What are the vertices of the ellipse?
topjm [15]

Answer:

The correct option is C.

Step-by-step explanation:

The given equation is

\frac{(x-6)^2}{16}+\frac{(y+7)^2}{4}= 1

It can be rewritten as

\frac{(x-6)^2}{4^2}+\frac{(y+7)^2}{2^2}= 1         .....(1)

The standard form of an ellipse is

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}= 1           ....(2)

Where (h,k) is center of the ellipse.

If a>b, then the vertices of the ellipse are (h\pm a, k).

From (1) and (2) we get

h=6,k=-7,a=4,b=2

Since a>b, therefore the vertices of the ellipse are

(h+a, k)=(6+4,-7)\Rightarrow (10,-7)

(h-a, k)=(6-4,-7)\Rightarrow (2,-7)

The vertices of the given ellipse are (10, –7) and (2, –7). Therefore the correct option is C.

5 0
3 years ago
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Since you are trying to isolate x, you will need to remove the 13 through division:


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Our answer is x = 6.

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4 years ago
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