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dolphi86 [110]
3 years ago
10

273.7 is what percent of 909.3.round to the nearest. whole number

Mathematics
1 answer:
sesenic [268]3 years ago
7 0
First, calculate 273.3 OF (x) 909.3:

273.3 x 909.3 = 248511.69

Now, let's round the product to the nearest whole number:

248511.69 = ~ 248512

Hope this helps!
Message me if you have any questions. :)
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I really need help i cant fail this
Nezavi [6.7K]

Answer:

Area\ of\ a\ trinagle = \frac{5}{12}x^2 or\ 0.42x^2

Step-by-step explanation:

Given:

Height of the triangle h = x

Base of the triangle b=\frac{5}{6}x

We need to find the area of the triangle.

Solution:

Using given Formula:

Area\ of\ a\ trinagle = \frac{1}{2}bh

Where:

b = Base of the triangle.

h = Height of the triangle.

Substitute h = x and b=\frac{5}{6}x in equation in given formula.

Area\ of\ a\ trinagle = \frac{1}{2}(\frac{5}{6})x\times x

Area\ of\ a\ trinagle = \frac{5}{12}x^2

Area\ of\ a\ trinagle =0.42x^2

Therefore, Area of the triangle is \frac{5}{12}x^2 or 0.42x^2.

6 0
4 years ago
Right in equation of the ellipse The rest of the question is in the photo
Tju [1.3M]

Answer:

1) The vertices are (-5 , 0) and (5 , 0)

  The co-vertices are (0 , -2) and (0 , 2)

  The foci are (-√21 , 0) and (√21 , 0)

2) The equation of the ellipse ⇒ x²/48 + y²/64 = 1

Step-by-step explanation:

1) ∵ 4x² + 25y² = 100 ⇒ ÷ 100

∴ x²/25 + y²/4 = 1

∵ The standard equation of the ellipse with center (0 , 0) is

   x²/a² + y²/b² = 1

∴ a² = 25 ⇒ ∴ a = ±5

∴ The vertices are (-5 , 0) and (5 , 0)

∴ b² = 4 ⇒ ∴ b = ±2

∴ The co-vertices are (0 , -2) and (0 , 2)

∵ c² = a² - b²

∴ c² = 25 - 4 = 21

∴ c = ±√21

∴ The foci are (-√21 , 0) and (√21 , 0)

2) ∵ Its center is (0 , 0)

∵ The vertex of it is (0 , -8)

∴ a² = 64

∵ The focus is (0 , 4)

∴ c² = 16

∵ c² = a² - b²

∴ b² = a² - c² = 64 - 16 = 48

∵ b² = 48

The standard equation of the ellipse with center (0 , 0) is

   x²/b² + y²/a² = 1 ⇒ major axis // to y-axis

∴ x²/48 + y²/64 = 1

6 0
3 years ago
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Answer:

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Given that :

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