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2 years ago

A shopper buys cat food in bags of 3 lbs. Her cat eats 3/4 alb each week. How many weeks does one bag last?

Mathematics

1 answer:

iren2701 [21]2 years ago

6 0

Divide 3 by 3/4 and you will get your answer. you can also multiply 3×4/3. it's the same thing

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At a fair, each person can spin two wheels of chance. The first wheel has the letters F, A, I, and R. The second wheel has the n

pickupchik [31]

Answer:

12 possible outcomes.

Sample space:

$\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}$

Step-by-step explanation:

The collection of all possible outcomes of a probability experiment forms a set that is known as the sample space.

1. There are four possible outcomes for the first wheel: F, A, I and R

2. There are three possible outcomes for the second wheel: 1, 2 and 3

So, the sample space is

$\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}$

4 0

2 years ago

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

5 0

1 year ago

Explain how you can estimate the volume of a large container that holds 5 rows of 4 snack-size boxes of cereal in its bottom lay

charle [14.2K]

Multiply the LxWxH to get the volume of something so in this situation multiply 5 x4x3 and u get ur awnsers

8 0

3 years ago

in a group of 15 people, two third of them are females, 4 of them are wearing boots. How many are not wearing boots

Mumz [18]

Answer:

6 females were not wearing boot but if your looking for how many people total aren't its 11 people that aren't

8 0

2 years ago

In a basketball game Anya makes 14 baskets. Some of these baskets were worth 2-points and others were worth 3-points. In total s

Tems11 [23]

Answer:

She made 12 two point basket.

Step-by-step explanation:

Assuming the number of 2 point basket is x and that of 3 point basket is y.

Based on the question the total numbers of basket is 14, that is x + y = 14 , and the total numbers of points is 30, which helps us with our second equation 2(x) +3(y)=30.

x + y = 14 eqn 1

2(x) +3(y)=30 eqn 2

Using elimination method multiplying eqn 1 by -3 and adding it to equation 2

-3x-3 y = -42 adding to eqn 2 gives

-x= -12

x=12. Which gives the number of the 2 points basket she made .

7 0

2 years ago