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3 years ago

15

Seriously need help working + answer

2 answers:

pychu [463]3 years ago

8 0

Square root of 2*3=square root 6 square root of 2*2=square root 4 square root of6+square root of4=square root 10 square root 10-square root 6=square root 4 answer=the square root of 4 which is 2 (am writing square because there is no square root sign in my laptop)

allsm [11]3 years ago

6 0

This is the answer (−1.550510257)

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Each True/ False question is worth 3 points and each multiple choice question is worth 5 points. If there is an 86- point test a

Leto [7]

Answer:

13

Step-by-step explanation:

x=true/false questions y = multiple choice

3x+5x=86

x+y=20

x=7, y=13

13 multiple choice questions

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2 years ago

What is the value of 3⁴

Andru [333]

Answer:

81 ............................

8 0

2 years ago

Read 2 more answers

Help please!!! i need it by 2:00 today. i will give brainliest

MA_775_DIABLO [31]

Answer:

Below in bold.

Step-by-step explanation:

x-intercepts (-3,0) and (6, 0)

y-intercept (0, -5)

Axis of symmetry:

(-3 + 6) / 2 = 1.5

x = 1.5.

Domain = all real x.

Range is f(x) ≥ -6.

Graph is positive for x < -3 and x > 6.

Negative for -3 < x < 6.

Increasing for x > 1.5 and decreasing for x < 1.5.

4 0

3 years ago

Please answer the following question:

ludmilkaskok [199]

Answer:

99 cm²

Step-by-step explanation:

1/2 BH

1/2 18 x 11

9 x 11

99

3 0

2 years ago

Use separation of variables to solve dy dx − tan x = y2 tan x with y(0) = √3. Find the value of c in radians, not degrees

a_sh-v [17]

Answer:

$y(x)=tan(-log(cos(x))+\frac{\pi }{3} )$

Step-by-step explanation:

Rewrite the equation as:

$\frac{dy(x)}{dx}-tan(x)=y(x)^{2} *tan(x)$

Isolating $\frac{dy}{dx}$

$\frac{dy}{dx} =tan(x)+tan(x)*y^{2}$

Factor:

$\frac{dy}{dx} =tan(x)*(1+y^{2} )$

Dividing both sides by $(1+y^{2} )$ and multiplying them by $dx$

$\frac{dy}{1+y^{2} } =tan(x)dx$

Integrate both sides:

$\int\ \frac{dy}{1+y^{2} } = \int\ tan(x) dx$

Evaluate the integrals:

$arctan(y)=-log(cos(x))+C_1$

Solving for y:

$y(x)=tan(-log(cos(x))+C_1)$

Evaluating the initial condition:

$y(0)=\sqrt{3} =tan(-log(cos(0))+C_1)=tan(-log(1)+C_1)=tan(0+C_1)$

$\sqrt{3} =tan(C_1)\\arctan(\sqrt{3} )=C_1\\60=C_1$

Converting 60 degrees to radians:

$60degrees*\frac{\pi }{180degrees} =\frac{\pi }{3}$

Replacing $C_1$ in the diferential equation solution:

$y(x)=tan(-log(cos(x))+\frac{\pi }{3} )$

3 0

2 years ago