Question

X^2+4x-1/(x+2)^2=0 solve for x

Answer 1

x^2+4x-1/(x+2)^2=0
x^2 + 4x - 1 = 0

$\frac{x^2+10x-7}{x^2+10x+25} =0\\x^2+10x-7=0\\x= \frac{-b\pm\sqrt{b^2-4ac}}{2a}$;
where a = 1, b = 4 and c = -1

$x=\frac{-4\pm\sqrt{4^2-(4\times1\times(-1)}}{2\times1}\\=\frac{-4\pm\sqrt{16+4}}{2}=\frac{-4\pm\sqrt{20}}{2}\\=\frac{-4\pm\sqrt{4\times5}}{2}=\frac{-4\pm2\sqrt{5}}{2}=-2\pm\sqrt{5}\\=-2+\sqrt{5} \ or \ -2-\sqrt{5}\\x=0.24 \ or \ x = -4.24$