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muminat
3 years ago
11

What is the leading coefficient of the polynomial? 7x + 5x2 − 9x3 − 10

Mathematics
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

The leading coefficient of the polynomial is -9.

Step-by-step explanation:

9 is the leading coefficient of this polynomial because if you rearrange the exponents from greatest to least, you will get this :

-9x3 + 5x2 + 7x -10

Your leading coefficient is the number included with your degree or highest exponent.

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Identify these prime numbers from the clues.
katen-ka-za [31]

Answer:

I the answer is:

a) 17

b) 37

6 0
3 years ago
Read 2 more answers
For each of the following studies, say whether you would use a t test for dependent means or a t test for independent means.
Shtirlitz [24]

Answer:

1. T test for independent means

2. T test for dependent means

3. T test for dependent means

Step-by-step explanation:

In number 1, the two groups are unrelated. The first group has 25 subjects and they're all unemployed. The second group has 24 subjects and their employment status is not stated and might not be the same all through. Also, the first group is receiving a new type of job skills program while the second group is taking the standard job skills program.

- The groups in the experiment are unrelated

- The tests in the research are unrelated

- The purpose of the research is unreasonable - the researcher seeks to measure how well all 49 subjects perform on 'a' job skills test! No comparison between the scores or mean scores of the two groups.

In number 2, the researcher uses the same subjects and also measures the same variable but twice. This is a good example of a study where the t test for dependent means can be taken. Same applies in case 3.

5 0
3 years ago
I hate math bro please help me ill mark u brainliest
yulyashka [42]
Please mark me brainless :)
5 0
3 years ago
Which of these is incorrect? A) 41,792 < 42,699 B) 42,699 > 43,595 Eliminate C) 42,699 < 44,792 D) 43,595 > 41,792
eimsori [14]
B is the correct answer
4 0
3 years ago
Read 2 more answers
Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A
MAVERICK [17]
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
    = -2cos4A*sin3A + 2cos4A*sinA
    = 2cos4A(sinA - sin3A)
    = 2cos4A*2cos(2A)sin(-A)
    = -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
   = 2cos4A*cos3A - 2cos4A*cosA
   = 2cos4A(cos3A - cosA)
   = 2cos4A*(-2)sin2A*sinA
   = -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
       = cos2A/sin2A
      = cot2A

This verifies the identity.
4 0
3 years ago
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