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Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6
Solution
In order to find greatest to least number, we have to convert the given fractions into decimals.
3 % = 3 + 1/10 = 3 + 0.10 = 3.10%
3 % = 3 + 2/5 = 3 + 0.40 = 3.40%
3 %= 3 + 0.25 = 3.25%
3 % = 3 + 0.33 = 3.33%
Now we can easily, compare the numbers and write from greatest to least.
3.40%, 3.33%, 3.25%, 3.10%
Greatest to least = 3 2/5%, 3 1/3%3, 3 1/4%, 1/10%,
Thank you :)
Answer:
Step-by-step explanation:
Formula to determine the scale factor,
Scale factor =
2 =
2 =
P'Q' = 4 cm
Similarly, for the length of A'B',
2 =
2 =
A'B' = 3 cm
For the length of M'N',
2 =
2 =
M'N' = 6 cm