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satela [25.4K]
4 years ago
13

What is the slope of the linear function represented in the table? -7

Mathematics
1 answer:
Minchanka [31]4 years ago
6 0

Answer:

The function is linear; therefore, the slope of the line joining any two points is the same. We take any two points from the table and compute the slope or rise/ run between them— let is take points (-4, -2) and (-2, -10).

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Math help pls o; will reward
BabaBlast [244]

Answer:

see explanation

Step-by-step explanation:

Expressing as equations

9x + 10y = 297 → (1) ← that is B

8x + 5y = 194 → (2) ← that is D

To solve the system of equations, multiply (2) by - 2

- 16x - 10y = - 388 → (3)

Add (1) and (3) term by term to eliminate the term in y

(9x - 16x) + (10y - 10y) = (297 - 388), that is

- 7x = - 91 ( divide both sides by - 7 )

x = 13

Substitute x = 13 into either of the 2 equations and solve for y

Using (1), then

(9 × 13) + 10y = 297

117 + 10y = 297 ( subtract 117 from both sides )

10y = 280 ( divide both sides by 10 )

y = 28

Cost of a small box of candy = $13

Cost of a large box of candy = $28

5 0
3 years ago
Read 2 more answers
A coat that cost $123 is marked 1/3 off what is the sale price of the coat
alina1380 [7]
I/3 of 123 is 41
41 dollars are taken off, so 123-41=82
the sale price is 82 dollars
4 0
3 years ago
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What is the value of f(-10) if f(x) = 4x - 12?​
IceJOKER [234]

F(-10) means the x value in the equation is -10.

Replace x with -10 and solve:

4(-10) -12 = -40 - 12 = -52

F(-10) = -52

3 0
3 years ago
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HELP <br>Which equations represent hyperbolas?
MissTica
An elliptical equation is in the form
Ax^2+Bx+Cy^2+Dy+E=0
the equation is a Hyperbola. When x and y are both squared, and exactly one of the coefficients is negative and exactly one of the coefficients is positive.
1-49x^2-98x-64y^2+256y-2831=0
2-4x^2+32x-25y^2-250y+589=0
3-81x^2+512x-64y^2-324y-3836=0
7 0
3 years ago
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Please help Need help
Anettt [7]
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where 
m=slope of line
(x0,y0) is a point through which the line passes.

We know that the line passes through A(3,-6), B(1,2)

All options have a slope of -4, so that should not be a problem.  In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.

So we can check which line passes through which point:

a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3)  means that line passes through A(3,-6) => ok

b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
   ****** this equation is not the line passing through A & B *****

c. y=-4x+6  subtract 2 from both sides (to make the y-coordinate 2)
   y-2 = -4x+4, rearrange
   y-2 = -4(x-1)  
   which means that it passes through B(1,2), so ok

d. y-2=-4(x-1)
   this is the same as the previous equation, so it passes through B(1,2), 
   this equation is ok.

Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
   
8 0
3 years ago
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