A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.
You scored a 625. Calculate your z-score to the nearest hundredth (i.e. 2 decimal places).
z=
1 answer:
Answer: 1.25
Step-by-step explanation:
Given: A college-entrance exam is designed so that scores are normally distributed with a mean
= 500 and a standard deviation
= 100.
A z-score measures how many standard deviations a given measurement deviates from the mean.
Let Y be a random variable that denotes the scores in the exam.
Formula for z-score = 
Z-score = 
⇒ Z-score = 
⇒Z-score =1.25
Therefore , the required z-score = 1.25
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Answer:
h(1)=-13

Step-by-step explanation:
We are given that

We have to find the recursive formula of h(n).
Substitute n=1

n=2

n=3


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Therefore, the recursive formula is given by
h(1)=-13

Answer:
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