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Papessa [141]
3 years ago
8

A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.

You scored a 625. Calculate your z-score to the nearest hundredth (i.e. 2 decimal places).
z=
Mathematics
1 answer:
Crank3 years ago
6 0

Answer: 1.25

Step-by-step explanation:

Given: A college-entrance exam is designed so that scores are normally distributed with a mean(\mu) = 500 and a standard deviation(\sigma) =  100.

A z-score measures how many standard deviations a given measurement deviates from the mean.

Let Y be a random variable that denotes the scores in the exam.

Formula for z-score = \dfrac{Y-\mu}{\sigma}

Z-score = \dfrac{625-500}{100}

⇒ Z-score = \dfrac{125}{100}

⇒Z-score =1.25

Therefore , the required z-score = 1.25

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h(n)=-13nh(n)=−13nh, left parenthesis, n, right parenthesis, equals, minus, 13, n Complete the recursive formula of h(n)h(n)h, l
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Step-by-step explanation:

We are given that

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h(n)=h(n-1)-13

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