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Alenkinab [10]
3 years ago
11

James is 10 feet below sea level if he increases his elevation by 30 feet what is his location?

Mathematics
1 answer:
puteri [66]3 years ago
8 0
His location would be 20 feet above the sea level because...

30+-10= 20 because adding a negative to a positive is basically like subtracting.

Can have a brainliest answer now please?
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F(x) = 5x2 + 20x - 12<br> What is the vertex for this
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Answer:

10+20x-12

20x-2

X=20-2

X=18

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The Andersons went to dinner at the Olive Garden. If their dinner cost $42.95 and they left a 15% tip for their server, how much
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$49.39 total. This is if you add the tip to the amount the dinner costs.
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Using the information given, write an equation in slope-intercept form.
Otrada [13]

Answer:

y = 2x + 3

General Formulas and Concepts:

<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

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y-intercept <em>b</em> = 3

<u>Step 2: Write function</u>

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8 0
3 years ago
Read 2 more answers
PLEASE HELP ITS DUE IN 5 MIN LIKE ACTUALLY Solve for x and upload a picture of your work (step-by-step):
kumpel [21]

Answer:

x = 4, 2

Step-by-step explanation:

You need to simplify:

- 10 I 5x - 5 I = - 150

+10                    +10

     I 5x - 5 I = - 140

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Can I have Brainliest please?

7 0
3 years ago
A tobacco company claims that the nicotine content of its "light" cigarettes has a mean of milligrams and a standard deviation o
valina [46]

The missing values in the given question is shown below.

A tobacco company claims that the nicotine content of its "light" cigarettes has a mean of 1.5 milligrams and a standard deviation of 0.52 milligrams. What is the probability that 50 randomly selected light cigarettes from this company will have a total combined nicotine content of 81 milligrams or less, assuming the company's claims to be true? Carry your intermediate computations to at least four decimal places. Report your result to at least three decimal places.

Answer:

P(x ≤ 1.62) = 0.949    to three decimal places.

Step-by-step explanation:

From the question; given that:

The population mean = 1.5

The standard deviation = 0.52

The sample size n = 50

The sample mean \overline x = \dfrac{81}{50} = 1.62

Hence; we can calculate the required probability as:

P( x \leq 1.62) = P \bigg (\dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{\overline x -1.5 }{\dfrac{\sigma}{\sqrt{n}}} \bigg )

P( x \leq 1.62) = P \bigg (Z \leq \dfrac{1.62 -1.5 }{\dfrac{0.52}{\sqrt{50}}} \bigg )

P( x \leq 1.62) = P \bigg (Z \leq \dfrac{0.12 }{\dfrac{0.52}{\sqrt{50}}} \bigg )

P( x \leq 1.62) = P \bigg (Z \leq 1.632 \bigg )

From z - tables;

P(x ≤ 1.62) = 0.9486

P(x ≤ 1.62) = 0.949    to three decimal places.

7 0
3 years ago
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