11/25
88/1000
Divide each by 8
11. Times 8
125 times 8
Answer:
I III and IV
Step-by-step explanation:
5a-15+9a=3a+29
We simplify the equation to the form, which is simple to understand
5a-15+9a=3a+29
We move all terms containing a to the left and all other terms to the right.
+5a+9a-3a=+29+15
We simplify left and right side of the equation.
+11a=+44
We divide both sides of the equation by 11 to get a.
a=4
Given:
m∠NRQ = 60°
To find:
The angle measure of minor arc NQ
Solution:
The inscribed angle is half of the intercepted arc.
![$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)](https://tex.z-dn.net/?f=%24%5CRightarrow%20m%5Cangle%20NRQ%20%3D%5Cfrac%7B1%7D%7B2%7D%20m%28ar%20NQ%29)
Multiply by 2 on both sides.
![$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)](https://tex.z-dn.net/?f=%24%5CRightarrow%202%20%5Ctimes%20m%5Cangle%20NRQ%20%3D2%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20m%28ar%20NQ%29)
![$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)](https://tex.z-dn.net/?f=%24%5CRightarrow%202%20%5C%20m%5Cangle%20NRQ%20%3Dm%28ar%20NQ%29)
Substitute m∠NRQ = 60°.
![$\Rightarrow 2\times 60^\circ=m(ar NQ)](https://tex.z-dn.net/?f=%24%5CRightarrow%202%5Ctimes%2060%5E%5Ccirc%3Dm%28ar%20NQ%29)
![$\Rightarrow 120^\circ=m(ar NQ)](https://tex.z-dn.net/?f=%24%5CRightarrow%20120%5E%5Ccirc%3Dm%28ar%20NQ%29)
The measure of minor arc NQ is 120°.