Answer:
The shadow is decreasing at the rate of 3.55 inch/min
Step-by-step explanation:
The height of the building = 60ft
The shadow of the building on the level ground is 25ft long
Ѳ is increasing at the rate of 0.24°/min
Using SOHCAHTOA,
Tan Ѳ = opposite/ adjacent
= height of the building / length of the shadow
Tan Ѳ = h/x
X= h/tan Ѳ
Recall that tan Ѳ = sin Ѳ/cos Ѳ
X= h/x (sin Ѳ/cos Ѳ)
Differentiate with respect to t
dx/dt = (-h/sin²Ѳ)dѲ/dt
When x= 25ft
tanѲ = h/x
= 60/25
Ѳ= tan^-1(60/25)
= 67.38°
dѲ/dt= 0.24°/min
Convert the height in ft to inches
1 ft = 12 inches
Therefore, 60ft = 60*12
= 720 inches
Convert degree/min to radian/min
1°= 0.0175radian
Therefore, 0.24° = 0.24 * 0.0175
= 0.0042 radian/min
Recall that
dx/dt = (-h/sin²Ѳ)dѲ/dt
= (-720/sin²(67.38))*0.0042
= (-720/0.8521)*0.0042
-3.55 inch/min
Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min
Step-by-step explanation:
1. secx / cscx
2. sinx /cosx
Step-by-step explanation:
Take a look at the picture, And tell me if am wrong
Answer:
(9x²)²
Step-by-step explanation:
Given the expression 81x⁴, to write the expression as a square of a monomial, first we will assign a variable to the expression.
y = 81x⁴
Then we take the square root of both sides of the expression
√y = √81x⁴
y^½ = √81 × √x⁴
y^½ = 9x²
Squaring both sides of the resulting equation to get y back
(y^½)² = (9x²)²
y = (9x²)²
The expression as a square of a monomial is (9x²)²
Answer:
50 units
Step-by-step explanation:
you use Pythagorean-theorem which means A^2+B^2 =C^2
It does not matter the order of A and B because it is adding. But C is the hypotenuse.
If we plug in the # this is what it looks like...
14^2 +48^2=C^2
or
48^2+14^2=C^2
14*14= 196
48*48=2,304
then you add
196+2,304=C^2
2,500= C^2
and you can use a calculator for this part you do 2,500
with the 2,500 you use the sign as in the picture and it gives you...
50
which means 50*50 = 2,500
