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3 years ago

Evaluate : f(x)= 3x - 4 , x=2

Mathematics

1 answer:

hram777 [196]3 years ago

6 0

Answer:

Step-by-step explanation:

3(2)-4

3*2=6

6-4=2

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Solve the rational equation. If an equation has no solution, so state.<br>x+6/x=-7

kupik [55]

Answer:

x=−1 or x=−6

Step-by-step explanation:

Multiply all terms by x and cancel:

xx+6=−7x

x2+6=−7x(Simplify both sides of the equation)

x2+6−−7x=−7x−−7x(Subtract -7x from both sides)

x2+7x+6=0

(x+1)(x+6)=0(Factor left side of equation)

x+1=0 or x+6=0(Set factors equal to 0)

x=−1 or x=−6

Check answers. (Plug them in to make sure they work.)

x=−1(Works in original equation)

x=−6(Works in original equation)

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3 0

2 years ago

Select the correct answer.

Delicious77 [7]

<h3>Answer: C -<u><em> Tracking Client's Investments</em></u>' </h3>

Step-by-step explanation: The reason for a personal finance manager is to keep track of your investments, and keep it logged down on what you spend and what you spend it on. It's a smart way to save, and easily manage your money!

8 0

2 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

2 years ago

Alexis sold 3/8 of her raffle tickets on the first day. She sold 88 raffle tickets during the first week and the remaining 32 ra

Ahat [919]

She would have sold 45 tickets on the first day

7 0

2 years ago

fifteen out of the 60 eighth-graders at sebring junior high are on the track team. what percent of the eight-graders are on the

allsm [11]

Answer:

25%

Step-by-step explanation:

You have 60 total, 30 on the track team would be 50%, but there is only 15 on the track them, you cut the 50% in half again which gives 25%.

8 0

3 years ago