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kap26 [50]
2 years ago
6

If M Need help asap ...................

Mathematics
1 answer:
aleksandrvk [35]2 years ago
5 0

The measure of angle DAC must be 60 degrees. Since a right angle is 90 degrees, the sum of the degrees of both of the angles must be that amount. If angle BAD is 30 degrees, the measure of angle DAC must be 60 degrees.

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Help would be very helpful :) the answers are: (812pi cm^3) (602pi cm^3) (735 cm^3) and (512pi cm^3) 30 points!!!!!
g100num [7]

Find the area of the top ( circle) then multiply by the height.

Area = pi x r^2

Area = pi x 7^2

Area = 49pi

Volume = 49pi x 15

Volume = 735pi cubic cm.

6 0
3 years ago
Find the slope of the line containing the two points (1,-1) and (-5,-3)
Strike441 [17]
Slope =(-3 + 1)/(-5 - 1) = -2/-6 = 1/3

answer
1/3
4 0
3 years ago
If the vertex of a parabola is (4,-6), what is the axis of symmetry?
Serhud [2]

Answer:

x = 4

Step-by-step explanation:

4 0
2 years ago
Use substitution to solve the following system of equations.
Diano4ka-milaya [45]
d+e-f=-3 \\
e=f+d+7 \\
f=2e-6 \\ \\
\hbox{substitute 2e-6 for f in the 2nd equation and solve for e:} \\
e=2e-6+d+7 \\
e=2e+d+1 \ \ \ |-2e \\
-e=d+1 \ \ \ |\times (-1) \\
e=-d-1 \\ \\
\hbox{substitute -d-1 for e in the 3rd equation and solve for f:} \\
f=2(-d-1)-6 \\
f=-2d-2-6 \\
f=-2d-8

\hbox{substitute -d-1 for e and -2d-8 for f in the 1st equation and solve for d:} \\
d+(-d-1)-(-2d-8)=-3 \\
d-d-1+2d+8=-3 \\
2d+7=-3 \ \ \ |-7 \\
2d=-10 \ \ \ |\div 2 \\
d=-5 \\ \\ e=-d-1=-(-5)-1=5-1=4 \\ \\
f=-2d-8=-2 \times (-5)-8=10-8=2 \\ \\
\boxed{d=-5} \\ \boxed{e=4} \\ \boxed{f=2} \\
\hbox{answer D}
5 0
3 years ago
Find the value of r so that the line through (-4,3) and (r,-3) has a slope of 2/3.
Tems11 [23]

Answer:

<h3>r = -13</h3>

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the slope m = 2/3 and the points (-4, 3) and (r, -3). Substitute:

\dfrac{-3-3}{r-(-4)}=\dfrac{2}{3}

\dfrac{-6}{r+4}=\dfrac{2}{3}        <em>cross multiply</em>

2(r+4)=(-6)(3)        <em>divdide both sides by 2</em>

r+4=(-3)(3)

r+4=-9       <em>subtract 4 from both sides</em>

\boxed{r=-13}

6 0
2 years ago
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