Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
Answer:
9 cm
Step-by-step explanation:
27 / 3 =9 cm
The total periméter is 27 and it has 3 sides so just divide
Answer:
C.

.
Step-by-step explanation:
Let r represent the cost of one packet of radish seeds and let t represent the cost of one packet of tomato seeds.
Roman spent $62.75
This implies that,

Roman bought 32 packets of seeds and one packet of radish seeds costs
$ 1.75.
One packet of tomato seeds costs $ 2.50.
This implies that,

Using guess and check means we substitute into the given equation.
A) We substitute

into both equations.



Both equations are not satisfied.
B)
We substitute

into both equations.



Both equations are not satisfied.
C)
We substitute

into both equations.



Both equations are satisfied.
Hence the solution is,

D) We substitute

into both equations.



Both equations are not satisfied.
Answer:

Step-by-step explanation:-
As per the statement:
Quinton bought x number of shares for p dollars and paid a 0.5% commission
⇒
It is also given that: He sold the stock for y dollars and paid a flat fee of $7.
⇒
then;
Net proceeds is given as:

Therefore, Quinton's net proceeds algebraically is 