4 and 3 fifths
To get that you divide 20 by 5 and put the 3 over the 5
Hope that helped you
Answer:
41.7feet
Step-by-step explanation:
From the question we are given the following
angle of depression = 50°
Distance of the pole from the base of the feet = 35feet (Adjacent)
Required
height of the school (opposite)
Using the SOH CAH TOA identity
Tan theta = opp/adj
Tan 50 = H/35
H = 35tan 50
H = 35(1.1918)
H = 41.7feet
Hence the height of the school is 41.7feet
Answer:
y = 3x^2 + 12x + 8
Step-by-step explanation:
To rewrite in standard from by expanding the equation using the distributive property.
y= 3 (x+2)^2 - 4
y = 3(x^2 + 4x + 4) - 4
y = 3x^2 + 12x + 12 - 4
y = 3x^2 + 12x + 8
Step-by-step explanation:
<h3>An exterior angle is equal to the addition of two angles not right next to it. The two exterior angles at each vertex are = in measure because they are vertical angles.</h3>
Let's call a child's ticket 
and an adult's ticket 
. From this, we can say:
,
since 116 tickets are sold in total.
Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus
.
Given these values, we can say:
,
since each adult ticket costs 17,000 and each child's ticket costs 12,750, and these costs sum to 1,653,250.
Now, we have two equations:
Let's solve:
- Find on its own, which will allow us to substitute it into the first equation
- Substitute in
for
- Apply the Distributive Property
- Subtract 1972000 from both sides of the equation and multiply both sides by -1
We have now found that 75 child's tickets were sold. Thus,
,
41 adult tickets were sold as well.
In sum, 41 adult tickets were sold along with 75 child tickets.
