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Vlad1618 [11]
3 years ago
10

What is the correct solution to the equation?

Mathematics
2 answers:
RSB [31]3 years ago
5 0

Answer:

B

Step-by-step explanation:

4(7-3)=16

7-3=4

4x4=16

Please mark brainliest!

Rom4ik [11]3 years ago
4 0

Answer:

B. 7

Step-by-step explanation:

4(x-3)=16 so you have to multiply the entire equation by 4 since it is outside parenthesis

4x-12=16 then you have to add 12 to both sides to isolate 4x

   +12  +12

4x=28 then you have to divide both sides by  to just have x

4/4=1  28/4=7 (the 1 doesn't mater because 1x=x and x=1x)

x=7 is your answer

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Answer:

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Step-by-step explanation:

First, you have to find the length of hypotenuse using Pythagoras' Theorem, c² = a² + b² :

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In order to find θ, you have to apply Sine Rule :

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Answer:

The center of the circle is c=50 and radius of the circle is r=\sqrt{3}

Step-by-step explanation:

Given circle equation is

x^2-4x+y^2+14y=-50\hfill(1)

Equation (1) can be written as x^2-4x+y^2+14y+50=0\hfill(2)

we know that the equation of the circle is of the form

x^2+y^2+2gx+2fy+c=0\hfill(3)

with centre (-g,-f) and radius=\sqrt{g^2+f^2-c}

when, g,f and c are constants

Now comparing the (2) and (3) equations we get 2g=-4

                                                                          g=\frac{-4}{2}

                                                                          g=-2

                                                                          2fy=14

                                                                          f=\frac{14}{2}

                                                                          f=7

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                  centre=(-g,-f)

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                  Radius=\sqrt{g^2+f^2-c}

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                             =\sqrt{4+49-50}

                            =53-50

                   Radius=\srqt{3}

The center of the circle is c=50 and the radius of the circle equation r=\sqrt{3}

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