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bagirrra123 [75]
3 years ago
11

Hi I need help with problems 14-16

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0
16 is $32
idk the others.... sorry.
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What is the value of x
Andru [333]
The answer to your question is 54 because you have to bring over 2 to 3 and it would be 1x then bring over 52 and add it to 2 = 54
8 0
2 years ago
S the following statement always, sometimes, or never true?
liubo4ka [24]

The statement <em>“The supplement of an acute angle is an obtuse angle.”</em> is always true because the sum of any two supplementary angles is 180°, so if one of them less than 90° (acute), then the other must be greater than 90° (obtuse)

Step-by-step explanation:

Let us revise some facts about the supplementary angles

  • Supplementary angles are two angles the sum of their measure is 180°
  • The two angles could be right angles or one of them is acute and the other is obtuse
  • The two angles can not be acute angles or obtuse angles

Let us take some examples to explain the facts above

∵ One of two supplementary angles is a right angle

∵ The measure of the right angle is 90°

∵ The sum of the measures of the supplementary angles is 180°

∴ 90 + the measure of the supplement angle = 180

- Subtract 90 from both sides

∴ The measure of the supplement angle = 90°

∴ The supplement of a right angle <u><em>must be</em></u> a right angle

∵ One of two supplementary angles is 70°

∵ Its measure less than 90°

∴ This angle is an acute angle

∵ The sum of the measures of the supplementary angles is 180°

∴ 70 + the measure of the supplement angle = 180

- Subtract 70 from both sides

∴ The measure of the supplement angle = 110°

∵ Its measure greater than 90°

∴ The supplement angle is an obtuse angle

∴ The supplement of an acute angle <u><em>must be</em></u> an obtuse angle

The two supplementary angles can not be acute angles because their sum is less than 180°

The two supplementary angles can not be obtuse angles because their sum is greater than 180°

The statement <em>“The supplement of an acute angle is an obtuse angle.”</em> is always true because the sum of any two supplementary angles is 180°, so if one of them less than 90° (acute), then the other must be greater than 90° (obtuse)

Learn more:

You can learn more about the supplementary angles in brainly.com/question/11175936

#LearnwithBrainly

4 0
3 years ago
Read 2 more answers
Plzz help its only 1 question!!!
andrew11 [14]

Answer:

D is correct

rost beef sandwich=7$

turkey sandwich=5$

Step-by-step explanation:

8 0
2 years ago
PLZ HELP ?
ollegr [7]
I think it’s seventy five
5 0
3 years ago
Read 2 more answers
Hi. Please I need help with these questions.
ElenaW [278]

Answer:

Q 12 roots of the equation

2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\

∝ = \frac{\sqrt{10} }{2}

β = -\frac{\sqrt{10} }{2}

no matter if u oppose the root

(i) 2(\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2} )^{2}+2(\frac{\sqrt{10} }{2} )^{2}(-\frac{\sqrt{10} }{2})+2(

(ii)((\frac{\sqrt{10} }{2})^{2} - 3 (\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2}) + ((-\frac{\sqrt{10} }{2})^{2}) = \frac{25}{2}

Q 13  roots of equation

4x^{2} -3x-4=0\\\alpha = -0.693\\\beta = 1.443

the roots of the second equation are

x1 = 1/3(-0.693) = -0.231

x2 = 1/3(1.443) = 0.481

the equation is

(x+0.231)(x-0.481)=0

x^{2}-\frac{1}{4} x-\frac{1}{9}

4 0
3 years ago
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