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3 years ago

Please help! A parallelogram has an area of 396 square centimeters and a height of 18 centimeters.

1 answer:

7 0

The area formula for a parallelogram is base*height=area. Make an equation. You know the area and the height, so plug that into the equation, and you get x*18=396. Solve for x by dividing 396 by 18 and you get 22. So, the base is 22cm.

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Given the sample −4, −10, −16, 8, −12, add one more sample value that will make the mean equal to 3.

Agata [3.3K]

Answer: The value to add to the set is 52

=======================================================

For a moment, ignore the extra value we'll add in later.

The given set of values add to -34.

Let x be the extra value we add in. It adds to the -34 to get -34+x, then we divide by 6 because the set {-4,-10,-16,8,-12,x} has 6 items.

So we get the mean (-34+x)/6

Set this equal to the mean we want (3) and solve for x

(-34+x)/6 = 3

-34+x = 6*3

-34+x = 18

x = 18+34

x = 52

The set {-4,-10,-16,8,-12,x} updates to {-4,-10,-16,8,-12,52} and this set has a mean of 3.

6 0

3 years ago

Suppose a company produces report indicates that the surveyed distance between two points is 1200 feet with a margin of error of

Otrada [13]

<h2>Hello!</h2>

The answers are:

$MaximumDistance=1200.1ft\\MinimumDistance=1199.9ft$

Since we are given the margin of error and it's equal to ±0.1 feet, and we know the surveyed distance, we can calculate the maximum and minimum distance. We must remember that margin of errors usually involves and maximum and minimum margin of a measure, and it means that the real measure will not be greater or less than the values located at the margins.

We know that the surveyed distance is 1200 feet with a margin of error of ±0.1 feet, so, we can calculate the maximum and minimum distances that the reader could assume in the following way:

$MaximumDistance=ActualDistance+0.1feet\\\\MaximumDistance=1200feet+0.1feet=1200.1feet$

$MinimumDistance=ActualDistance-0.1feet\\\\MaximumDistance=1200feet-0.1feet=1199.9feet$

Have a nice day!

4 0

3 years ago

What is 5r^2 = 80<br><br> It says solve each equation with the quadratic formula.

katovenus [111]

$5r^2 = 80 \ \ /:5\\ \\r^2=\frac{80}{5}\\ \\r^2=16\\ \\r^2-16=0\\ \\ r^2 - 4^2 =0 \\ \\(r-4)(r+4)=0$

$r-4=0 \ \ \vee \ \ r+4 =0 \\ \\r=4 \ \ \vee \ \ r = -4 \\ \\ \\ a^2-b^2 = (a- b)(a+b)$

5 0

3 years ago

A rectangle has a height of a² + 3 and a width of a² + 2a + 5.

valentina_108 [34]

Answer:

Area = $a^4+2a^3+8a^2+6a+15$

Step-by-step explanation:

The area of a rectangle is given by:

Area = Height * Width

The expressions for height and width are given. We just need to multiply and add like terms (if applicable) to find the expression for the area of the rectangle.

Remember to use distributive property:

$(a+b)(x+y) = ax + ay + bx + by$

Thus, we have:

$(a^2+3)(a^2+2a+5)\\=(a^2)(a^2)+(a^2)(2a)+(a^2)(5)+3a^2+6a+15\\=a^4+2a^3+5a^2+3a^2+6a+15\\=a^4+2a^3+8a^2+6a+15$

THis is the expression for area.

5 0

3 years ago

WILL GIVE BRAINLIEST !!!

wel

Answer:

72-12k plz mark brainlest

Step-by-step explanation:

7 0

3 years ago