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tangare [24]
3 years ago
10

82. Use properties of exponents to rewrite each expression with only positive, rational exponents. Then find the numerical value

of each expression when x = 9, y= 8, and z= 16. In each case, the expression evaluates to a rational number.
b. 11√y2z4
Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

11yz² and when evaluating we get 22528

Step-by-step explanation:

We have the expression 11\sqrt{y^{2}z^{4}  }

We know that a square root is a 1/2 exponent, so we're going to multiply the exponents of y and z by 1/2.

11\sqrt{y^{2}z^{4}  }= 11y^{2(1/2)}z^{4(1/2)} }  =11yz^{2}

Therefore the expression is rewritten as 11yz^2

Now we're going to evaluate this expression for y = 8 and z = 16

11yz^{2} =11(8)(16)^2=88(256)=22528

Thus, when evaluated the result is 22528

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The answer is 4.7x -11.6
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72 oz = lb<br> feel in blank
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Since we know 16 ounces equal a pound, we just need to divide 72 by 16.

72/16 = 4.5

Your answer should be 4.5 pounds. Hope this helps!
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3 years ago
Which number belongs in the integers area on the Venn diagram?
Whitepunk [10]

Answer:

-19      - Integer

-5       - Integer

12       - Whole Number

14.25 - Rational Numbers

Step-by-step explanation:

Whole numbers = {0, 1 , 2, 3, . . . }

They are the the natural numbers and zero.

Integers: {. . . , -3, -2, -1, 0 , 1, 2, 3, . . . }

Rational Numbers: These are the numbers that can be written in the form of $ \frac{p}{q} $ where $ q \ne 0 $.

Note that All Whole numbers are integers.

All Integers are in turn Rational Numbers. (When q = 1, we get all the integers.).

In the given problem, we have: -19 Negative number. It should be an Integer.

Similarly -5 is also an integer.

12 is a whole number. Note that it is also an integer. Consequently, a rational number.

And 14.25 = $ \frac{1425}{100} $ is in the form of $ \frac{p}{q} $. So it is a rational number.

7 0
4 years ago
In 2008, there were 507 children in Arizona out of 32,601 who were diagnosed with Autism Spectrum Disorder (ASD) ("Autism and de
Svetach [21]

Answer:

The 99% confidence interval for the proportion of ASD in Arizona is (0.014, 0.018).

Step-by-step explanation:

The information provided is as follows:

x=507\\n=32601\\\text{Confidence level }=99\%

The sample proportion is:

\hat p=\frac{x}{n}=\frac{507}{32601}=0.016

The critical value of <em>z</em> for 99% confidence level is, <em>z</em> = 2.56.

Compute the 99% confidence interval for the proportion of ASD in Arizona as follows:

CI=\hat p\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p(1-\hat p)}{n}}

    =0.016\pm 2.58\cdot\sqrt{\frac{0.016(1-0.016)}{32601}}\\\\=0.016\pm 0.0018\\\\=(0.0142, 0.0178)\\\\\approx (0.014, 0.018)

Thus, the 99% confidence interval for the proportion of ASD in Arizona is (0.014, 0.018).

6 0
3 years ago
Suppose a subdivision on the southwest side of Denver, Colorado, contains 1,500 houses. The subdivision was built in 1983. A sam
mihalych1998 [28]

Answer:

0.0268 = 2.68% probability that the sample average is greater than $229,500

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Single house:

The mean appraised value of a house in this subdivision for all houses is $228,000, with a standard deviation of $8,500, which means that \mu = 228, \sigma = 8.5

Sample:

Sample of 120, so, by the central limit theorem, n = 120, s = \frac{8.5}{\sqrt{120}} = 0.7759

What is the probability that the sample average is greater than $229,500?

This is 1 subtracted by the pvalue of Z when X = 229.5. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{229.5 - 228}{0.7759}

Z = 1.93

Z = 1.93 has a pvalue of 0.9732

1 - 0.9732 = 0.0268

0.0268 = 2.68% probability that the sample average is greater than $229,500

7 0
3 years ago
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