1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ad-work [718]
2 years ago
8

In 2008, there were 507 children in Arizona out of 32,601 who were diagnosed with Autism Spectrum Disorder (ASD) ("Autism and de

velopmental," 2008). Find the proportion of ASD in Arizona with a confidence level of 99%.
Mathematics
1 answer:
Svetach [21]2 years ago
6 0

Answer:

The 99% confidence interval for the proportion of ASD in Arizona is (0.014, 0.018).

Step-by-step explanation:

The information provided is as follows:

x=507\\n=32601\\\text{Confidence level }=99\%

The sample proportion is:

\hat p=\frac{x}{n}=\frac{507}{32601}=0.016

The critical value of <em>z</em> for 99% confidence level is, <em>z</em> = 2.56.

Compute the 99% confidence interval for the proportion of ASD in Arizona as follows:

CI=\hat p\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p(1-\hat p)}{n}}

    =0.016\pm 2.58\cdot\sqrt{\frac{0.016(1-0.016)}{32601}}\\\\=0.016\pm 0.0018\\\\=(0.0142, 0.0178)\\\\\approx (0.014, 0.018)

Thus, the 99% confidence interval for the proportion of ASD in Arizona is (0.014, 0.018).

You might be interested in
Complete the steps to solve for x.
mylen [45]
Answer: 11

Explanation:

(4/5)x - (1/4)x = 11
(16/20)x - (5/20)x = 11
(11/20)x = 11
7 0
2 years ago
Read 2 more answers
The tens digit is 9 more than the ones digit my number is?
yKpoI14uk [10]
90 or 100 something like that.
5 0
3 years ago
el jefe decidió agregar la tabla de frecuencias correspondiente a la edad de sus empleados tal Como se muestra a continuación Cu
lapo4ka [179]

Answer:

Average employee [Mean] = 43.6

Step-by-step explanation:

Given:

Interval   Number of employee

25-35                      20

35-45                      7

45-55                      8

55-65                     15

Total                       50

Find:

Average employee [Mean]

Computation:

Interval     X[u+l]/2 Number of employee   fx

25-35         30           20                              600

35-45         40             7                              280

45-55         50            8                              400

55-65         60            15                             900

Total                           50                            2,180

Average employee [Mean] = Sum of fx / Sum of x

Average employee [Mean] = 2,180 / 50

Average employee [Mean] = 43.6

5 0
3 years ago
EXTRA POINTS<br> will mark BRAINLIEST!<br> I only need 10, 11 , 16, 18 &amp;19
LuckyWell [14K]

Answer:

10, 11 , 16, 18 &19

Step-by-step explanation:

  • \geq \neq \int\limits^a_b {x} \, dx \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]
6 0
3 years ago
Will give brainliest answer !!<br><br> ig- 513_kaylee<br> tiktok- ..theekaylee<br> sc- kkcutie14
wel

Answer:

90

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Other questions:
  • fran swims at a speed of 2.4 mph in still water, the river flows at a speed of 0.6mp, how long will it take fran to swim 2.7mi u
    10·1 answer
  • What set of values could be the side lengths of 30-60-90 triangles
    5·1 answer
  • How many people own a SUV?<br> A. 4<br> B. 42<br> C. 420<br> D. 4,200
    12·1 answer
  • Andrew has 40/100 of dollars. What are two possible combinations of coins that he could have?
    8·2 answers
  • 4 pts Question 3 Justify the reason for similarity in the triangles below with a similarity postulate. 9 3 5 15 M AA SSS Not Sim
    15·1 answer
  • Find the inequalities represented by the graph ​
    8·1 answer
  • In a highschool, 2/5 of the boys make up 250 students. how many boys are there in the high school?
    13·1 answer
  • 5 yd<br> .<br> 6 yd<br> Byd<br> Click Here:
    14·1 answer
  • Please help me asap with explanation please ​
    8·2 answers
  • ?/1
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!