19*19 is 34 so I’m sure its 19
(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0
Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º (360º-53.13º=306.87)
sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º
The solutions when 0≤x≤360º are: 36.87º and 306.87º.
I'm not to sure maybe b ?
1+38*225(12/77)
1+38*225*6.41
1*8550*6.41
1+54,805.5
54,806.5
Use pemdas to solve it
Answer: $13,846.02
Step-by-step explanation:
The car cost $29,750 when it was first bought.
It will then depreciate at a rate of 12% per year. This means that the value of the car reduces by 12% per year.
To find the value of the car in the 6th year, you can use the compound interest formula:
= Value of car * ( 1 - rate) ^ no. of years
= 29,750 * ( 1 - 12%)⁶
= 13,816.021581824
= $13,846.02
