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disa [49]
4 years ago
11

Pls help me answer this math question , I will give brainiest to the correct person .

Mathematics
1 answer:
Pie4 years ago
7 0
Hi,

\sqrt{5}  = 2.23 \\  \\ 2.23 \times 2.23 = x \\ 4.9729 = x \\ x = 4.9729  \approx5

Hope this helps.
r3t40
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Show that x²-8x+20 can be written in the form (x-a)²+a where a is an integer
Fiesta28 [93]

Answer:

   x² - 8x + 20

=  x²- 2*4*x + 16 + 4

=  x²- 2*4*x + 4² + 4

= (x - 4)² + 4

= (x - a)² + a, with a = 4

Hope this helps!

5 0
3 years ago
Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°.
inna [77]

Answer:

First part

The answer is (5 square root 2, 45°), (-5 square root 2, 225°) ⇒ answer (d)

Second part

The equation in standard form for the hyperbola is y²/81 - x²/19 = 1 ⇒ answer(b)

Step-by-step explanation:

First part:

* Lets study the Polar form and the Cartesian form

- The important difference between Cartesian coordinates and

  polar coordinates:

# In Cartesian coordinates there is exactly one set of coordinates

  for any given point.

# In polar coordinates there is an infinite number of coordinates

   for a given point. For instance, the following four points are all

   coordinates for the same point.

# In the polar the coordinates the origin is called the pole, and

  the x axis is called the polar axis.

# The angle measurement θ can be expressed in radians

   or degrees.

- To convert from Cartesian Coordinates (x , y) to

  Polar Coordinates (r , θ)

# r = ± √(x² + y²)

# θ = tan^-1 (y / x)

* Lets solve the problem

- The point in the Cartesian coordinates is (5 , 5)

∵ x = 5 and y = 5

∴ r = ± √(5² + 5²) = ± √50 = ± 5√2

∴ tanФ = (5/5) = 1

∵ tanФ is positive

∴ Angle Ф could be in the first or third quadrant

∵ Ф = tan^-1 (1) = 45°

∴ Ф in the first quadrant is 45°

∴ Ф in the third quadrant is 180 + 45 = 225°

* The answer is (5√2 , 45°) , (-5√2 , 225°)

Second part:

* Lets study the standard form of the hyperbola equation

- The standard form of the equation of a hyperbola with  

  center (0 , 0) and transverse axis parallel to the y-axis is

  y²/a² - x²/b² = 1, where

• the length of the transverse axis is 2a

• the coordinates of the vertices are (0 , ±a)

• the length of the conjugate axis is 2b

• the coordinates of the co-vertices are (±b , 0)

•      the coordinates of the foci are (0 , ± c),  

• the distance between the foci is 2c, where c² = a² + b²

* Lets solve our problem

∵ The vertices are (0 , 9) and (0 , -9)

∴ a = ± 9 ⇒ a² = 81

∵ The foci at (0 , 10) , (0 , -10)

∴ c = ± 10

∵ c² = a² + b²

∴ (10)² = (9)² + b² ⇒ 100 = 81 + b² ⇒ subtract 81 from both sides

∴ b² = 19

∵ The equation is  y²/a² - x²/b² = 1

∴  y²/81 - x²/19 = 1

* The equation in standard form for the hyperbola is y²/81 - x²/19 = 1

3 0
3 years ago
Tell whether each point is on the graph of f(x)=|x|.If it is, give the coordinates of another point with the same y value.
julsineya [31]
Show the online answer to this but I say 5
7 0
3 years ago
Tom, Ted, Tony and Terry worked together on a job. The job paid $500. Each boy was paid according to the amount of work he contr
skelet666 [1.2K]
<span>For the answer to the question above,
Let d be Ted's portion; y be Tony's ; r be Terry's ; m be Tom''s
d+y+r+m=500
d+y+0+0=280
d+0+0+m=260
d+0+r+0=220
-----------
Using the Matrix function of a TI calculator to solve this system
of equations I get:
Ted = $130 ; so Ted did 130/500 = 26%
Tony= $150 ; so Tony did 150/500= 30%
Terry=$90 ; so Terry did 90/500= 18%
Tom = $130 ; so Tom did 130/500 = 26%</span>
7 0
4 years ago
The product of 2/5a²x and -1/5x²a is?
Natasha2012 [34]
So you first multiply the fractions: 2/5 times -1/5 = -2/25; then the a's: a^2 times a equals a^3; then multiply the x's: x times x^2 equals x^3.
The answer would be -2/25a^3x^3
7 0
3 years ago
Read 2 more answers
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