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Studentka2010 [4]
3 years ago
5

The product of 2/5a²x and -1/5x²a is?

Mathematics
2 answers:
Natasha2012 [34]3 years ago
7 0
So you first multiply the fractions: 2/5 times -1/5 = -2/25; then the a's: a^2 times a equals a^3; then multiply the x's: x times x^2 equals x^3.
The answer would be -2/25a^3x^3
fredd [130]3 years ago
7 0

<u>Answer:</u>

- \frac {2} {25} a^3 x^3

<u>Step-by-step explanation:</u>

We are given the following terms and we are to multiply them and find their product:

\frac{2} {5} a^2x and -\frac {1} {5} x^{2} a

Multiplying the two terms:

\frac{2} {5} a^2x × -\frac{1} {5} x^{2} a

Taking the LCM and adding the like exponents of the like terms to get:

-\frac{2}{25} a^3x^3

Therefore, the product of the given terms is -\frac{2}{25} a^3x^3.

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Answer:

1/4

Step-by-step explanation:

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CBA = 4 C'B'A'

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5 0
2 years ago
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Dima020 [189]

Step-by-step explanation:

Total tomato plants = 24 + 30 = 54

Total green bean plants = 18 + 25 = 43

The ratio of tomato plants to green bean plants

=  \frac{54}{43}  = 54 \:  :  \: 43

4 0
3 years ago
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Help with #7 please I don’t understand
quester [9]

Answer:

A

Step-by-step explanation:

(2x^2 + 3x - 4) (x + 4)


FOIL.


2x^2 times x = 2x^3

3x times x is 3x^2

-4 times x = -4x

2x^2 times 4 = 8x^2

3x times 4 = 12 x

-4 times 4 = -16


Combine like terms to get 2x^3 + 11x^2 + 8x - 16.

4 0
2 years ago
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Simplify (-4 + 5i) + 2(1 + 3i). Enter your answer in the form a + bi.
luda_lava [24]

(-4 + 5i) + 2(1 + 3i)

  • Distribute 2 inside the parentheses.

(-4 + 5i) + 2 + 6i

  • Combine like terms.
<h3>-2 + 11i</h3>
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5 0
3 years ago
If you divide one of the roots of the equation 4x2+bx−27=0 by the other root, the quotient will be −3. Find b.
klio [65]
<h3>Answer:</h3>

  ±12   (two answers)

<h3>Explanation:</h3>

Suppose one root is <em>a</em>. Then the other root will be -3<em>a</em>. The product of the two roots is the ratio of the constant coefficient to the leading coefficient:

  (<em>a</em>)(-3<em>a</em>) = -27/4

  <em>a</em>² = -27/(4·(-3)) = 9/4

  <em>a</em> = ±√(9/4) = ±3/2

Then the other root is

  -3<em>a</em> = -3(±3/2) = ±9/2 . . . . . . the roots will have opposite signs

We know the opposite of the sum of these roots will be the ratio of the linear term coefficient to the leading coefficient: b/4, so ...

  -(a + (-3a)) = b/4

  2a = b/4

  b = 8a = 8·(±3/2)

  b = ±12

_____

<em>Check</em>

For b = 12, the equation factors as ...

  4x² +12x -27 = (2x -3)(2x +9) = 0

  It has roots -9/2 and +3/2, the ratio of which is -3.

For b = -12, the equation factors as ...

  4x² -12x -27 = (2x +3)(2x -9) = 0

  It has roots 9/2 and -3/2, the ratio of which is -3.

4 0
3 years ago
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