The answer is Stan twiceushisnsskkemr
If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
We can use the Front Outside Inside Last (FOIL) method to expand the double bracket
Front ⇒
Outside ⇒
Inside ⇒
Last ⇒
Put the four terms together we have
, then collect like terms
Answer:
hey there buddy
Step-by-step explanation: