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timurjin [86]
3 years ago
5

What is another way to write 9 times 200

Mathematics
2 answers:
evablogger [386]3 years ago
5 0

There are a lot of ways but one of thm are

200(9)

lord [1]3 years ago
4 0

100x2x9

(50x4)9

(40x5) x9

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When a number is written in scientific notation, could zero ever be in the ones place of the first factor? Which digits, if any,
makkiz [27]
No there couldn't and there is none
3 0
3 years ago
Which inequality is equivalent to X-4 <9?
Sergeu [11.5K]

<em>Answer</em><em> </em><em>with</em><em> </em><em>explanation</em><em>:</em>

The Given Inequality is

  |x-4|<9

Modulus of a number yields always a positive value.

→|x-4|= x-4, when, x-4≥0

                     That is , x≥4.

         = -(x-4), when, x-4<0

                    means, x<4.

     it can be Written as

 → -9<x-4<9

→ -9+4 < x -4+4 < 9+4

→ -5<x<13

→x∈(-5,13)

♡ <em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>♡</em>

4 0
4 years ago
Read 2 more answers
Evaluate the equation;<br><br> 38 + 16 ⋅ 12 ÷ 2 - (30 ⋅ 2)
Aleks04 [339]
The answer would be 74
8 0
3 years ago
Read 2 more answers
a garden is made up of two squares and a quarter circle. what are the perimeter and area of the garden
FrozenT [24]
The complete question in the attached figure

Part A) find the perimeter
[perimeter of the garden]=[perimeter square 1]+[perimeter a quarter circle]+[perimeter square 2]

[perimeter square 1]=5+5+5-----> 15 ft
[perimeter square 2]=5+5+5-----> 15 ft
[perimeter a quarter circle]=(2*pi*r)/4------> 2*pi*5/4-----> 7.85 ft

[perimeter of the garden]=[15]+[7.85]+[15]-------> 37.85 ft

the answer Part A) is
the perimeter of the garden is 37.85 ft

Part B) Find the area of the garden

[Area of the garden]=[Area square 1]+[Area a quarter circle]+[Area square 2]

[Area square 1]=5*5-----> 25 ft²
[Area square 2]=5*5-----> 25 ft²
[Area a quarter circle]=(pi*r²)/4------> pi*5²/4-----> 19.625 ft²

[Area of the garden]=[25]+[19.625]+[25]-------> 69.625 ft²

the answer Part B) is
the Area of the garden is 69.625 ft²


8 0
3 years ago
A marketing research firm would like to survey undergraduate and graduate college students about whether or not they take out st
neonofarm [45]

Answer:

Objective Minimize 10x1 +15x2 + 12x3+18x4+15x5+ 21x6

The central total cost $ 17586 due to the number of central undergraduate students 1458 is very high.

The total minimum cost would $ 17586 +$260+ $300= $ 18146

Step-by-step explanation:

Let

X1 = # of undergraduate students from the East region,

X2 = # of graduate students from the East region,

X3 = # of undergraduate students from the Central region,

X4 = # of graduate students from the Central region,

X5 = # of undergraduate students from the West region, and

X6 = # of graduate students from the West region.

Then  the cost functions are

y1= 10x1 +15x2

y2= 12x3+18x4

y3= 15x5+ 21x6

According to the given conditions

The constraints are

x1 +x2 + x3+x4+ x5+ x6 ≥ 1500------- A

15X2 +18X4+21X6 ≥ 400---------B

21X6 ≥ 100

X6 ≥ 100/21

X6 ≥ 4.76

Taking

X6= 5

10X1 ≤ 500

X1 ≤ 500/10

X1≤ 5

18X4 ≥ 75

X4 ≥ 75/18

X4 ≥ 4.167

Taking

X4= 5

Putting the values

15X5+ 21X6 ≥ 300

15X5+ 21(5) ≥ 300

15X5+ 105 ≥ 300

15X5 ≥ 300-105

15X5 ≥ 195

X5 ≥ 195/15

X5 ≥ 13

Putting value of X6 and X4 in B

15X2 +18X4+21X6 ≥ 400

15X2 +18(5)+21(5) ≥ 400

15X2 +195 ≥ 400

15X2  ≥ 400-195

15X2  ≥ 205

X2  ≥ 205/15

X2  ≥ 13.67

Taking X2= 14

Now putting the values in the cost equations to check whether the conditions are satisfied.

y1= 10x1 +15x2

y1= 10 (5) + 15(14)= 50 + 210= $ 260

y3= 15x5+ 21x6

y3= 15 (13) + 21(5)

y3= 195+105= $ 300

x1 +x2 + x3+x4+ x5+ x6 ≥ 1500

5+14+x3+5+13+5≥ 1500

x3≥ 1500-42

x3≥ 1458

y2= 12x3+18x4

y2= 12 (1458)  + 18 (5)

y2= 17496 +90

y2= $ 17586

The cost can be minimized if the number of students from

                                 Undergraduate         Graduate

East Region              X1≤ 5                            X2  ≥ 13.67

Central                      X3≥ 1458                   X4 ≥ 4.167

West                          X5 ≥ 13                          X6 ≥ 4.76

This will result in the required number of students that is 1500

Constraints:

East Undergraduate must not be greater than 5

East Graduate must not be less than 13

Central Undergraduate must  be greater than 1458

Central Graduate must  be greater than 4

West Undergraduate must  be greater than 13

West Graduate must  be greater than 4

The central total cost $ 17586 due to the number of central undergraduate students 1458 is very high.

The east region has a least cost of $260 and west region has a cost of $300.

The total minimum cost would $ 17586 +$260+ $300= $ 18146

6 0
3 years ago
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