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Sav [38]
3 years ago
11

Find the product of monomials 3a^4b^-2 and 2a^7b^-1

Mathematics
1 answer:
Inga [223]3 years ago
5 0
(3a^4 * b^-2) * (2a^7 * b^-1)
= 6*a^(4+7)*b^(-2-1)
= 6*a^11*b^-3
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Step-by-step explanation:

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In the equation x/35 = 7, what is the value of x? <br> A. 35 <br> B. 245 <br> C. 7 <br> D. 5
tensa zangetsu [6.8K]
The equation given in the question has one unknown variable in the ofrm of "x" and there is also a single equation. So it can be definitely pointed out that the exact value of the unknown variable "x" can be easily determined. Now let us focus on the equation given in the question.
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8 0
3 years ago
49767269 x 327686000 - 1029 + 1101 / 32
mars1129 [50]

Answer:

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Step-by-step explanation:

49767269 × 327686000 - 1029 + \frac{1101}{32}

= 16308037309534000 - 1029 + \frac{1101}{32}

= 16308037309532972 + 34\frac{13}{32}

= 16308037309533006\frac{13}{32}

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