Find the product of monomials 3a^4b^-2 and 2a^7b^-1

1 answer:

Inga [223]3 years ago

5 0

(3a^4 * b^-2) * (2a^7 * b^-1)
= 6*a^(4+7)*b^(-2-1)
= 6*a^11*b^-3

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