9514 1404 393
Answer:
B. loga(p) = m
Step-by-step explanation:
Equivalent forms are ...

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<em>Additional comment</em>
It helps me to remember that a logarithm is an exponent. The base of the exponent is the base of the logarithm.
9514 1404 393
Answer:
Step-by-step explanation:
These "special" right triangles have side length ratios that it is useful to remember.
<u>45°-45°-90° triangle</u>
Sides have the ratios 1 : 1 : √2. That is, x is √2 times as long as the side length shown as 18.
x = 18√2
<u>30°-60°-90° triangle</u>
Shortest to longest, sides have the ratios ...
1 : √3 : 2
That is, y is √3 times the length of the side marked 18, and z is 2 times the length of the side marked 18.
y = 18√3
z = 2·18 = 36
First, an introduction: If the equation of the circle were x^2 + y^2 = 144, then the center would be at (0,0) and the radius would be 12. Note that the distance from the center to P(10,10) is 10sqrt(2), or 14.14. Thus, in this example, P would be OUTSIDE the circle (since 14.14 is greater than the radius 12).
Now let's focus on <span>(x-1)^2 + (y-2)^2 =144. Let x = 12 as an example; find the corresponding y: 9^2 + (y-2)^2 = 144, or (y-2)^2 = 63, and so y-2 is approx. -8 or +8. Then y (for x = 12) is either approx. -10 or 6: (12,-10) or (12,6). Are these inside the circle or outside?
A better way to address this would be as follows:
Find the distance from the center (1, 2) to the point P(10,10). If this distance is less than 12, the point P is inside C; if greater than 12, P is outside C.
This distance is sqrt( (10-2)^2 + (10-1)^2 ), or sqrt (64+81) = sqrt(145).
This is LARGER than sqrt(144). Thus, P is OUTSIDE the circle C.</span>
Answer:
B
Step-by-step explanation:
600+12000+12000+35000=59600