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xxTIMURxx [149]
3 years ago
13

Use d=1/2gt^2 and solve for the time one spends moving upward in a 0.6-m vertical jump. Then double it for the "hang time"-the t

ime ones feet are off the ground.
Mathematics
1 answer:
oee [108]3 years ago
5 0
Hi there how are you feeling today
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What is the mean of the following set of numbers?
amm1812

Answer:

C. 279.3

Step-by-step explanation:

To find the mean of a set of numbers you have to add all of them together and divide them by how manys numbers there are

If we add all the numbers together it equals 2514

There are 9 numbers here

2514/9=279,333333

Therefore, the answer is C

5 0
3 years ago
Read 2 more answers
Shen needs to read 2 novels each month
Sonbull [250]

Answer:

Equation: N = 2M, Shen needs to read 26 novels in 13 months

Step-by-step explanation:

Given : Shen needs to read 2 novels each month.

i.e. In One month , the number of novels read by Shen = 2

Let N be the number of novels Shen needs to read in M months.

Then , N = 2 M

Thus , the equation relating N to M : N = 2 M

If Number of months = 13 , then put M = 13 in the above equations , we get

N = 2(13) = 26

Hence, the number of novels he read in 13 months = 26.

5 0
2 years ago
HELP I NEED RIGHT ANWSER QUICK!!!
9966 [12]
What’s the question?????
7 0
3 years ago
Read 2 more answers
Jasmine used the number line to find the distance between 0 and 5. What was Jasmine’s error? Jasmine should have counted from 5
Jobisdone [24]

Answer:

The answer is "Option C".

Step-by-step explanation:

In this question, the distance value is -5 that's why option c is correct.

5 0
3 years ago
Solve for x. Evaluate and round your answer to 1 decimal place (tenths place). 10x=3588
professor190 [17]

Answer:

<h2>x =3.6</h2>

Step-by-step explanation:

10^x=3588\\\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right)\\\ln \left(10^x\right)=\ln \left(3588\right)\\x\ln \left(10\right)=\ln \left(3588\right)\\\mathrm{Solve\:}\:x\ln \left(10\right)=\ln \left(3588\right):\quad x=\frac{\ln \left(3588\right)}{\ln \left(10\right)}\\\\= 3.55485\\=3.6

5 0
3 years ago
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