Step-by-step explanation:
Hey there!!!
Here,
Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.
The equation of a straight line passing through point is,

Now, put all values.

It is the 1st equation.
Another equation is;
y = 5x +2........(2nd equation).
Now, Comparing it with y = mx + c, we get;
m2=5
As per the condition of perpendicular lines,
m1×m2= -1
m1 × 5 = -1
Therefore, m2= -1/5.
Keeping the value of m1 in 1st equation.

Simplify them.



Therefore the required equation is x+5y+8= 0.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer: 2 then 1
Step-by-step explanation:
Just did it
Answer:
Equation: 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 5/6
Step-by-step explanation:
Unit means 1
Therefore a each 1/6 is the multiple unit of 5/6 because if we had all the 1/6 together, you get 5/6. There is 1 over 6 which you can tell that it is a unit fraction.
Find the Greatest Common Factor (GCF)
<u>GCF = 6y^6</u>
Factor out the GCF. (Write the GCF first. Then, in parenthesis divide each term by the GCF.)
6y^6(24y^8/6y^6 + 6y^6/6y^6)
Simplify each term in parenthesis
<u>6y^6(4y^2 + 1)</u>
Answer:
50 feet
Step-by-step explanation:
We have to find the perimeter of the fence surrounding the garden.
2l+2w
2(15) + 2(10)
30 + 20
= 50
50 feet will be needed.