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2 years ago

Which recursive formula can be used to generate the sequence below, where f(1) = 3 and n ≥ 1?

Mathematics

2 answers:

Lady_Fox [76]2 years ago

7 0

Answer:

The answer is C

Step-by-step explanation:

Llana [10]2 years ago

4 0

Answer:

$f(n)=-2\cdot f(n-1)$ , where f(1)=3

Step-by-step explanation:

The given sequence is; 3, –6, 12, –24, 48, …

The first term of this sequence is

$f(1)=3$

There is a common ratio of $r=\frac{-6}{3}=-2$

We can actually use any other two consecutive terms in the sequence to obtain the common ratio.

The recursive formula is given by:

$f(n)=r\cdot f(n-1)$

We plug in the common ratio to get:

$f(n)=-2\cdot f(n-1)$ , where f(1)=3

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Any help is appreciated

8_murik_8 [283]

Answer:

It can't be C or D. I think it could be A.

7 0

3 years ago

Read 2 more answers

For an outdoor concert by the city orchestra, concert organizers estimate that 16 comma 000 people will attend if it is not rai

Sladkaya [172]

Answer: 13300

========================================

Work Shown:

A = event that it rains

B = event that it does not rain

P(A) = 0.30

P(B) = 1-P(A) = 1-0.30 = 0.70

Multiply the attendance figures with their corresponding probabilities

if it rains, then 7000*P(A) = 7000*0.30 = 2100
if it doesn't rain, then 16000*P(B) = 16000*0.70 = 11200

Add up the results: 2100+11200 = 13300

This is the expected value. This is basically the average based on the probabilities. The average is more tilted toward the higher end of the spectrum (closer to 16000 than it is to 7000) because there is a higher chance that it does not rain.

3 0

3 years ago

Use <, =, or > to complete the statement. 0.62 0.16

Kobotan [32]

The Statement would be: 0.16 < 0.62

6 0

3 years ago

Read 2 more answers

Solve: x³-7x²+36=0.

Aliun [14]

Answer:

3,6,-2

Step-by-step explanation:

a+2a+b = 7

2a^2b = -36

a*2a + ab + 2ab = 0

or, a(2a+3b) = 0

so, b = -2a/3

Solve those and you find 3,6,-2

3 0

2 years ago

Tyler is offered to choose between three boxes that look identical. The first box contains 1 red pills and 19 blue pills, the se

Dafna1 [17]

Answer:

A) 0.15

B) 0.36

Step-by-step explanation:

First Box consist 1 red pills and 19 blue pills

second box consist 6 red pills and 14 blue pills

Third box consist 2 red pills and 18 blue pills

a) Prob ( randomly chosen pill is red) $= \frac{1}{3} \times \frac{1}{20} + \frac{1}{3} \times \frac{6}{20} + \frac{1}{3} \times \frac{2}{20}$

$\frac{1}{60} (1+6+2) = 0.15$

b)Prob ( 1 reds and 10 blue pilss) = $\frac{1}{3} \frac{^1C_1\times ^{19}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^6C_1\times ^{14}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^2C_1\times ^{18}C_{10}}{^{20}C_{11}}$

$= \frac{1}{3} 1.106 = 0.368$

7 0

2 years ago