Which recursive formula can be used to generate the sequence below, where f(1) = 3 and n ≥ 1?
2 answers:
Answer:
, where f(1)=3
Step-by-step explanation:
The given sequence is; 3, –6, 12, –24, 48, …
The first term of this sequence is
There is a common ratio of
We can actually use any other two consecutive terms in the sequence to obtain the common ratio.
The recursive formula is given by:
We plug in the common ratio to get:
, where f(1)=3
You might be interested in
Answer:
sin^2(θ)+cos^2(θ)=1
Step-by-step explanation:
We know that the statement above is true because of the Pythagorean identity theorem, which states the aforementioned equation. If you solve the equation for 1 you get the same equation.
To do this first multiply both sides by cos(θ), this gives you (cos^2θ)/1+sinθ = 1-sinθ
Then, multiply both sides by sinθ. This equals cos^θ=1-sin^2θ.
Finally, add sin^2θ to both sides. This equals the final answer of cos^2θ+sin^2θ=1. Which is true.
