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2 years ago

Find the value of x. Then find the angle measures of the polygon.

Mathematics

1 answer:

Bess [88]2 years ago

4 0

Question 11

x+x+1/2x+1/2x=360

x+x+2/2x+=360

x+x+x=360

3x=360

x=120

Then substitute 120 in the place of x

x1=120

x2=120

1/2(120)=60

To check your answer you can add 60+60+120+120 the should be equal to 360

Question 12

x+x+(x-45)+(x-45)+(x-45)=540

x+x+x-45+x-45+x-45=540

5x-135=540

5x=540+135

5x=675

x=675/5

x=135

Then substitute 135 in the place of x

x1=135

x2=135

135-45=90

To check your answer you can add 135+135+90+90-90 the should be equal to 540

Hope it helps

Please give brainliest

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makkiz [27]

Answer:

Absolute error = 13-12.7=0.3

13 =100%

12.7=x

x=(12.7)(100)/13

x=97.7

the percentage error is 97.7%

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3 years ago

Train A and Train B leave the station at 2 P.M. The graph below shows the distance covered by the two trains. Compare the speeds

adoni [48]

Answer:

Train b is moving faster than a by 45 units an hour

Step-by-step explanation:

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3 years ago

Please answer this correctly

BlackZzzverrR [31]

Answer:

9.5 ft

Step-by-step explanation:

The perimeter is equal to

P =2(l+w)

29.6 = 2(5.3+z)

Divide each side by 2

29.6 /2 =2/2(5.3+z)

14.8 = 5.3 +z

Subtract 5.3 from each side

14.8-5.3 = z

9.5 =z

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3 years ago

Read 2 more answers

The following figure is made of six semicircles with the same diameter, and of four congruent equilateral triangles represented

Oxana [17]

6 semicircles = 3 circles

The formula of the area of a equilateral triangle:

$A_\triangle=\dfrac{a^2\sqrt3}{4}$

We have a = |AE| = 3cm. Substitute:

$A_\triangle=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\ cm^2$

The formula of the area of a circle:

$A_O=\pi r^2$

We have 2r = |AE| =3cm → r = 1.5cm. Substitute:

$A_O=\pi\cdot1.5^2=2.25\pi\ cm^2$

The area of the figure:

$A=4A_\triangle+3A_O\\\\A=4\cdot\dfrac{9\sqrt3}{4}+3\cdot2.25\pi=9\sqrt3+6.75\pi=6\dfrac{3}{4}\pi+9\sqrt3\\\\=\dfrac{27}{4}\pi+\dfrac{36\sqrt3}{4}=\dfrac{9}{4}\cdot3\pi+\dfrac{9}{4}\cdot4\sqrt3=\dfrac{9}{4}(3\pi+4\sqrt3)\ cm^2$

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3 years ago

You are choosing between two different cell phone plans. The first plan charges a rate of 25 cents per minute. The second plan c

bogdanovich [222]

Answer:You would have to use over 200 minutes in a month in order for the second plan to be preferable.

Step-by-step explanation:

Let x represent the number of minutes that you use in a month.

The first plan charges a rate of 25 cents per minute. It means that the cost of using x minutes in a month with this plan is 0.25x.

The second plan charges a monthly fee of $29.95 in addition to 10 cents per minute. It means that the cost of using x minutes in a month with this plan is

29.95 + 0.1x

For the second plan to be preferable, its cost would be lesser than the first plan. Therefore,

29.95 + 0.1x < 0.25x

29.95 < 0.25x - 0.1x

29.95 < 0.15x

0.15x > 29.95

x > 29.95/0.15

x > 200

4 0

3 years ago