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amid [387]
3 years ago
5

What is the circumference

Mathematics
1 answer:
Butoxors [25]3 years ago
5 0
Are you asking for the definition of circumference? because you didn’t attach a picture or give us an equation to do.
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The markup on a restaurant meal is 250%. A meal costs $7.30 to produce. How much will the customer be charged before tax and tip
Brums [2.3K]
x. 250
_____ _____
7.30 100

cross multiply

100x = 1825

divide the 100

x = 18.25



5 0
3 years ago
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A 26-foot long ladder is leaning against a building at a 60 degree angle with the ground.
Anvisha [2.4K]
A. 

csc is equal to the opposite divided by the hypotenuse. 
8 0
3 years ago
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165321 rounded to the nearest ten thousand
olya-2409 [2.1K]

Answer:

170,000

Step-by-step explanation:

Look at the placeholder digits, go on to the ten thousands digit, look at the following number and then round up or down and make all following digits 0.

5 0
2 years ago
Consider the two triangles.
GuDViN [60]

Answer:

(A)Show that the ratios StartFraction U V Over X Y EndFraction , StartFraction W U Over Z X EndFraction , and StartFraction W V Over Z Y EndFraction are equivalent.

\dfrac{UW}{XZ}=\dfrac{WV}{ZY}=\dfrac{UV}{XY}

Step-by-step explanation:

In Triangles WUV and XZY:

\angle VUW$ and \angle YXZ$ are congruent. \\\angle U W V$ and \angle X Z Y$ are congruent.\\ \angle U V W$ and \angle Z Y X$ are congruent.

Therefore:

\triangle UWV \cong  \triangle XZY

To show that the triangles are similar by the SSS similarity theorem, we have:

\dfrac{UW}{XZ}=\dfrac{WV}{ZY}=\dfrac{UV}{XY}

As a check:

\dfrac{UW}{XZ}=\dfrac{40}{32}=1.25\\\\\dfrac{WV}{ZY}=\dfrac{60}{48}=1.25\\\\\dfrac{UV}{XY}=\dfrac{50}{40}=1.25

The correct option is A.

4 0
3 years ago
Jamal's deck is in the shape of a polygon and is shown on the grid below.(-8,6)(6,6)o[(-8, -4),(6,-4)What is the area of Jamal's
PSYCHO15rus [73]

Let;

A(-8,6) B(6,6) C(6, -4) D(-8, -4)

Let's find the length AB

x₁= -8 y₁=6 x₂=6 y₂=6

We will use the distance formula;

d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}

=\sqrt[]{(6+8)^2+(6-6)^2}=\sqrt[]{14^2+0}=14

Next, we will find the width BC

B(6,6) C(6, -4)

x₁= 6 y₁=6 x₂=6 y₂=-4

substitute into the distance formula;

d=\sqrt[]{(6-6)^2+(-4-6)^2}

=\sqrt[]{(-10)^2}=\sqrt[]{100}=10

Area = l x w

= 14 x 10

= 140 square units

7 0
1 year ago
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