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LenKa [72]
3 years ago
9

What is the value of a in the equation 5a - 10b = 45, when b = 3?

Mathematics
2 answers:
AURORKA [14]3 years ago
7 0

Answer:

         

Step-by-step explanation:

                                    n    

c

 

timurjin [86]3 years ago
5 0

Answer:15

Step-by-step explanation: Substitute the values into the equation and solve

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Find the slope of the line whose equation is 15 + 3x = 2y.
Korvikt [17]
15+3x=2y
2y=3x+15
y=\frac{3}{2} x+ \frac{15}{2}
Gradient, m= \frac{3}{2}
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If Kendra started working at 10:30 a.m. and left at 6:15 p.m., how many hours of work should she record for the day on her time
Tom [10]
<span>From 12 PM to 6 PM is 6 hours From 11 AM to 12 PM is 1 hour We are left with 30 minutes (from 10:30 AM to 11 AM) + 15 minutes (from 6 PM to 6:15 PM), so total time (add up what we have) is 7 hours and 45 minutes.</span>
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for every 6 girls on the softball team there are 9 boys on the baseball team if there are 50 students on both teams how many are
taurus [48]
Key info-there are nine boys for every six girls on the softball team

9/6

9(3)=27. 6(3)18

18+27=45 5 more to go

if there is 50 students on each of the teams

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6(8)=48

As one can see,they both cannot multiply up to 50,but they round up.
5 0
3 years ago
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Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
3 years ago
Plz answer!!!!!!!!!!!!!!​
makkiz [27]

Answer:

7

Step-by-step explanation:

i know

7 0
2 years ago
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