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Natalka [10]
3 years ago
15

Which phrase is equivalent to “Franco must work a minimum of 32 hours”? The number of hours Franco works must be less than 32. T

he number of hours Franco works must be greater than 32. The number of hours Franco works must be less than or equal to 32. The number of hours Franco works must be greater than or equal to 32.
Mathematics
1 answer:
Butoxors [25]3 years ago
8 0

Answer:

The number of hours Franco works must be greater than or equal to 32.

Step-by-step explanation:

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When fireworks display made of copper is burned, it lets out light with wavelengths, v v, that satisfy the relationship | v − 45
Xelga [282]

Answer:

See attached picture.

Step-by-step explanation:

See attached picture for detailed explanation.

5 0
3 years ago
An advertising company charges $40 per half-page advertisement and $75 per full-page advertisement. Michael has a budget of $800
TEA [102]

Answer:

full page = 8

half page = 5

Step-by-step explanation:

two equations can be derived from the question

40x + 75y = 800 equation 1

x + y = 13 equation 2

x = number of half page advertisement

y = number of full page advertisement

multiply equation 2 by 40

40x + 40y = 520 equation 3

subtract equation 3 from 2

280 = 35y

y = 8

substitute for y in equation 2

x + 8 = 13

x = 13 - 8

x = 5

6 0
3 years ago
Whats 63/100-5/10? with an good 5th grade explanation​
Ilia_Sergeevich [38]

Answer:  .13

Step-by-step explanation:

63/100=0.63

5/10=0.50

=.13

I took 63 and divided it by 100 to get .63 and took 5 and divided it by 10 to get .50 so I took them and subtracted them to get .13

4 0
3 years ago
Please give an explanation.<br>​
aev [14]
Replace the variable x with -4 in the expression.

f (- 4) = 3(- 4)^2 - (- 4) + 23

Simplify each term.

f (- 4) = 48 + 4 + 23

Simplify by adding numbers.

f (- 4) = 75

The final answer is 75.
6 0
4 years ago
Find the real or imaginary solutions of each equation by factoring
anyanavicka [17]
Sum of  2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so

x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4

the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
for x²-4x+16=0
x=\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(16)} }{2(1)}
x=\frac{4+/- \sqrt{16-64} }{2}
x=\frac{4+/- \sqrt{-48} }{2}
x=\frac{4+/- (\sqrt{-1})(\sqrt{48}) }{2}
x=\frac{4+/- (i)(4\sqrt{3}) }{2}
x=2+/- 2i\sqrt{3}


the roots are
x=-4 and 2+2i√3 and 2-2i√3
8 0
3 years ago
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