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3 years ago

Simplify 3 radical sign 128-2 radical sign 6•4 radical sign 3. Show all work. Please help me it’s due today!!!

Mathematics

1 answer:

alexdok [17]3 years ago

7 0

Answer:

Step-by-step explanation:

3*sqrt(128) - 2sqrt(6)*4sqrt(3)

3*sqrt(128) = 3*sqrt(64*2) But the square root of 64 = 8

3sqrt(128) = 3*8 * sqrt(2) = 24 sqrt(2)

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2* sqr(6)*4sqrt(3) Combine the 2 and 4 = 8. Break apart the 6.

8* sqrt(3*2)*sqrt(3) Break apart the sqrt(3*2)

8*sqrt(3*2)*sqrt(3) = 8 * sqrt(3)*sqrt(2)*sqrt(3) but sqrt(3)*sqrt(3) = 3

8*sqrt(3)*sqrt(2)*sqrt(3) = 8*3*sqrt(2) = 24sqrt(2)

===================

24sqrt(2) - 24*sqrt(2)

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3 years ago

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<h3>hello!</h3>

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3 years ago

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3 years ago

HURRY PLEASE! I BEG ITS FOR POINTS

gtnhenbr [62]

Answer:

1 and 3

Step-by-step explanation:

Given the system of two equations

$\left\{\begin{array}{l}Px+Qy=R\\ \\Tx+Uy=V\end{array}\right.$

When you add, subtract, multiply the equations of the system, you get equivalent system of equations (with the same solution).

1. Add these two equations to get the system

$\left\{\begin{array}{l}Px+Qy=R\\ \\Px+Tx+QY+Uy=R+V\end{array}\right.\Rightarrow \left\{\begin{array}{l}Px+Qy=R\\ \\(P+T)x+(Q+U)y=R+V\end{array}\right.$

Hence, option 1 is correct.

2. Multiply the second equation by 2 and add two equations:

$\left\{\begin{array}{l}Px+Qy=R\\ \\2Tx+2Uy=2V\end{array}\right.\Rightarrow \left\{\begin{array}{l}Px+Qy=R\\ \\(P+2T)x+(Q+2U)y=R+2V\end{array}\right.$

Since $R+2V\neq R-2V,$ this option is false

3. Subtract two equations:

$\left\{\begin{array}{l}Tx-Px+Uy-Qy=V-R\\ \\Tx+Uy=V\end{array}\right.\Rightarrow \left\{\begin{array}{l}(T-P)x+(U-Q)y=V-R\\ \\Tx+Uy=V\end{array}\right.$

Option 3 is correct.

4. Since $U-Q\neq Q+U$ , option 4 is false

5. Multiply the second equation by 5 and subtract the first equation:

$\left\{\begin{array}{l}Px+Qy=R\\ \\5Tx+5Uy=5V\end{array}\right.\Rightarrow \left\{\begin{array}{l}(5T-P)x+(5U-Q)y=5V-R\\ \\Tx+Uy=V\end{array}\right.$

Since $V-5R\neq 5V-R$ , this option is false.

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3 years ago