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Goryan [66]
2 years ago
11

Determine the value of X please help

Mathematics
1 answer:
bonufazy [111]2 years ago
5 0

Answer:

the angel?

Step-by-step explanation:

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Find the volume of the right cone.
3241004551 [841]

384π cm³ ( first one in list )

Calculate the volume (V) of the cone using the formula

V = \frac{1}{3} πr²h ( r is the radius and h the height )

here r = 12 and h = 8

V = \frac{1}{3} × 12² × 8 = 384π cm³ ← exact value



7 0
3 years ago
Reese is selling lemonade at the parade. He gets to keep 50% of the money he collects. A large lemonade is $6.00 and a small lem
yuradex [85]

Answer:

$5

Step-by-step explanation:

Given data

We are given that

Large lemonade= $6

Small lemonade= $4

Total amount = 6+4= $10

He keeps 50% of the total

= 50/100*10

=0.5*10

= $5

Hence he will keep $5

8 0
2 years ago
PLEASE HELP I NEED THIS FAST
iren2701 [21]

Answer:

Step-by-step explanation: the x side is +5 and the y side is -15

3 0
3 years ago
DOES ANYONE GET THIS? ):
KonstantinChe [14]

There is a given point (10,3) this shows that when the width (X) is 10, the height (Y) is 3.

On the left side of the graph, they show an equation for the height Hw as being the constant over w ( width).

Using the given point solve for the constant.

Replace Hw with 3 and w with 10:

3 = Constant/10

Solve for the constant by multiplying both sides by 10:

Constant = 3 x 10

Constant = 30

The answer is B.

7 0
3 years ago
Represent real-world situations a rectangular piece of sheet metal is rolled and riveted to form a circular tube that is open at
Citrus2011 [14]
<span>12.3 Volume function: v(x) = ((18-x)(x-1)^2)/(4pi) Since the perimeter of the piece of sheet metal is 36, the height of the tube created will be 36/2 - x = 18-x. The volume of the tube will be the area of the cross section multiplied by the height. The area of the cross section will be pi r^2 and r will be (x-1)/(2pi). So the volume of the tube is v(x) = (18-x)pi((x-1)/(2pi))^2 v(x) = (18-x)pi((x-1)^2/(4pi^2)) v(x) = ((18-x)(x-1)^2)/(4pi) The maximum volume will happen when the value of the first derivative is zero. So calculate the first derivative: v'(x) = (x-1)(3x - 37) / (4pi) Convert to quadratic equation. (3x^2 - 40x + 37)/(4pi) = 0 3/(4pi)x^2 - (10/pi)x + 37/(4pi) = 0 Now calculate the roots using the quadratic formula with a = 3/(4pi), b = -10/pi, and c = 37/(4pi) The roots occur at x = 1 and x = 12 1/3. There are the points where the slope of the volume equation is zero. The root of 1 happens just as the volume of the tube is 0. So the root of 12 1/3 is the value you want where the volume of the tube is maximized. So the answer to the nearest tenth is 12.3</span>
3 0
3 years ago
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