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grin007 [14]
3 years ago
14

Which of the following is a description of the data with a correlation coefficient of zero? low positive correlation low negativ

e correlation no correlation high negative correlation
Mathematics
2 answers:
Vlada [557]3 years ago
7 0
Because the coefficient is zero, there will be no correlation
ella [17]3 years ago
7 0

Answer:

the answer is C. No correlation

Step-by-step explanation:


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WILL GIVE BRAINLIEST PLZ HURRY
pshichka [43]

Answer:

C

Step-by-step explanation:

because it is asking to find the number of classes held during the weekday zumba class.

weekday class = 30 minutes

Saturday= 45 minutes

total = 165  

7 0
3 years ago
Simplify the expression to a polynomial in standard form: (4x+5) (x^2-3x-2) PLEASE HLEP
pickupchik [31]

Answer:

4x^3-7x^2-23x-10

Step-by-step explanation:

So we have the expression:

(4x+5)(x^2-3x-2)

Distribute. Multiply (4x+5) to each term:

(x^2)(4x+5)+(-3x)(4x+5)+(-2)(4x+5)

Distribute:

=(4x^3+5x^2)+(-12x^2-15x)+(-8x-10)

Combine like terms:

=(4x^3)+(5x^2-12x^2)+(-15x-8x)+(-10)

Add and simplify:

=4x^3-7x^2-23x-10

And this is in descending order, so it's in standard form.

7 0
3 years ago
For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

  • Divide row 1 by 2 \left(R_1=\frac{R_1}{2}\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]

  • Add row 3 multiplied by 6 to row 2 \left(R_2=R_2+\left(6\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

8 0
3 years ago
Can someone please help me with this?
fomenos

perimeter = Answer:

Step-by-step explanation:

5. Perimeter of semi circle = r(pi+2)

Given diameter=17m; r=17/2

Perimeter = (17/2)(pi+2)

6. Given diameter = 10.5

Perimeter = (10.5/2)(pi+2)

8 0
3 years ago
Joaquin wants to reduce the number of winners so he
zvonat [6]

Answer:

78

Step-by-step explanation:

8 0
3 years ago
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