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Julli [10]
3 years ago
6

What is value of x in the equation(x+ 4)^5 =3125

Mathematics
2 answers:
koban [17]3 years ago
7 0
(x + 4)^5 = 3125
(x + 4)(x + 4)(x + 4)(x + 4)(x + 4) = 3125
(x² + 4x + 4x + 16)(x² + 4x + 4x + 16)(x + 4) = 3125
(x² + 8x + 16)(x² + 8x + 16)(x + 4) = 3125
(x^4 + 8x³ + 16x² + 8x³ + 64x + 128x + 16x² + 128x + 256)(x + 4) = 3125
(x^4 + 8x³ + 8x³ + 16x² + 16x² + 64x + 128x + 128x + 256)(x + 4) = 3125
(x^4 + 16x³ + 32x² + 320x + 256)(x + 4) = 3125
x^5 + 4x^4 + 16x^4 + 64x³ + 32x³ + 128x² + 320x² + 1280x + 256x + 1024 = 3125
x^5 + 20x^4 + 96x³ + 448x² + 1536x + 1024 = 3125
<u>                                                             -1024   -1024</u>
            x^5 + 20x^4 + 96x³ + 448x² + 1536x = 2101
                                                                     x = 1

olga_2 [115]3 years ago
5 0
(X+4)^5=3125
Use distributive property for x and 5 and 4 and 5 to get
5x+20=3125
Then subtract 20 from both sides to get
5x=3105
Then divide both sides by 5 to get
X= 621
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Someone help me pls <br><br>47 as the sum of ______
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Answer:

  (a) 6² +3² +1² +1² = 47

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Step-by-step explanation:

It can work reasonably well to start with the largest square less than the target number, repeating that approach for the remaining differences. When more squares than necessary are asked for, then the first square chosen may need to be the square of a number 1 less than the largest possible.

The approach where a cube is required can work the same way.

(a) floor(√47) = 6; floor(√(47 -6^2)) = 3; floor(√(47 -45)) = 1; floor(√(47-46)) = 1

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(b) floor(√47 -1) = 5; floor(√(47-25)) = 4; ...

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(c) floor(∛47) = 3; floor(√(47 -27)) = 4; floor(√(47 -43)) = 2

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Step-by-step explanation:

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