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Sati [7]
3 years ago
9

pleaseeeee hlpppp. i just need the diagraam i can't figure it out.surveyor is measuring the length of a lake. He takes angle mea

surements from two positions, A and B that are 136 m apart and on the same side of the lake. From B, the measure of the angle betweet the sight lines to the ends of the lake is 130 degrees and the measure of the angle between the sight lines to A and one end of the lake is 120°. From A, the measure of the angle between the sight lines to the ends of the lake is 65 degrees, and the measure of the angle between the sight lines to B and the same end of the lake is 20 degrees Calculate the length of the lake, to the nearest metre. 20°..

Mathematics
1 answer:
kupik [55]3 years ago
7 0
<span>Let the distance from A to the ends of the lake be w and r . From the given it appears that

w / sin 104 = 136 / sin 56 and r / sin 120 = 136 / sin 15....solve for w & r.

then L² = r² + w² - 2 r w cos 65 , where L = length of the lake...

attached a picture



</span>

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Answer:

1.4 inches

Step-by-step explanation:

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Let the width of the mat be x. The mat has the same width all around the rectangular picture, so it adds x on each side of the length and x on each side of the width.

old length: 8

new length: 2x + 8

old width: 6

new width: 2x + 6

Area of the new rectangle with mat = new length * new width

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The new area is 96, so that give us an equation.

(2x + 8)(2x + 6) = 96

Use FOIL on the left side:

4x^2 + 12x + 16x + 48 = 96

Combine like terms, and subtract 96 from both sides:

4x^2 + 28x - 48 = 0

Divide both sides by 4:

x^2 + 7x - 12 = 0

To factor the trinomial, we need two numbers that add to 7 and multiply to -12. There are no such numbers, so we need to use the quadratic formula.

x = [-b +/- sqrt(b^2 - 4ac)]/(2a)

x = [-7 +/- sqrt(7^2 - 4(1)(-12)]/[2(1)]

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Since the mat cannot have a negative width, the negative solution is discarded.

Answer: The width of the mat is 1.4 inches.

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