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Lilit [14]
3 years ago
12

john needed 13.71 feet of wire to fix a lamp he bought 14 half feet of wire how much did he have left ver​

Mathematics
2 answers:
motikmotik3 years ago
8 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Just subtract the two values:

14.5 - 13.71 = 0.79

He had 0.79 feet of wire left

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

lakkis [162]3 years ago
3 0
If he had 4 half feet of wire, then he would have 7 feet of whole wire.

To find out how much more wire he needs, subtract how much he has so far from how much he totally needs.
13.71-7=6.71
He needs 6.71 more feet of wire.

Hope this helps!
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3 years ago
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bija089 [108]

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Given the limit of the function

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To simplify the function given, we will have to factor out the highest power of n which is n² from the numerator and the denominator. The function will then become;

2−7n+9n²/8n²+2n−6

= n²{2/n²-7/n+9}/n²{8+2/n-6/n²}

The n² at the numerator will then cancel out the n² at the denominator to have resulting simplified equation as;

{2/n²-7/n+9}/{8+2/n-6/n²}

Evaluating the limit of the resulting equation will give;

limn→[infinity] {2/n²-7/n+9}/{8+2/n-6/n²}

Note that limn→[infinity] a/n = 0 where a is any constant.

Therefore;

limn→[infinity] {2/n²-7/n+9}/{8+2/n-6/n²}

= (0-0+9)/(8+0-0)

= 9/8

Since the limit of the sequence gives a finite value which is 9/8, thus the sequence in question is a convergent sequence.

The limit of a sequence only diverges if the limit of such sequence is an infinite value.

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