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Lilit [14]
3 years ago
12

john needed 13.71 feet of wire to fix a lamp he bought 14 half feet of wire how much did he have left ver​

Mathematics
2 answers:
motikmotik3 years ago
8 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Just subtract the two values:

14.5 - 13.71 = 0.79

He had 0.79 feet of wire left

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

lakkis [162]3 years ago
3 0
If he had 4 half feet of wire, then he would have 7 feet of whole wire.

To find out how much more wire he needs, subtract how much he has so far from how much he totally needs.
13.71-7=6.71
He needs 6.71 more feet of wire.

Hope this helps!
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Your team catches 42 Mahi Mahi over 2 weeks. What is the average daily Mahi Mahi catch?
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2 weeks are 14 days so
42÷14= 3
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If rolando earned $28.50 in 2 hours, how much would he earn in 8 hours?
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First, we need to find his unit rate, the amount he earns in 1 hour.

So, we have to divide 28.50 by 2.

That is:

28.50 / 2 = $14.25 per hour

To find the amount he earns in 8 hours, we will need to multiply hourly rate found by "8". So,

14.25 * 8 = $114

<h2>Rolando earns $114 in 8 hours</h2>

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1 year ago
You work in the HR department at a large franchise. you want to test whether you have set your employee monthly allowances corre
ra1l [238]

Answer:

1) Null hypothesis:\mu \leq 500  

Alternative hypothesis:\mu > 500  

z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90  

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

z_{crit}= 2.33

For this case we see that the calculated value is higher than the critical value

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

2) Since is a right tailed test the p value would be:  

p_v =P(z>5.90)=1.82x10^{-9}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

Step-by-step explanation:

Part 1

Data given

\bar X=640 represent the sample mean

\sigma=150 represent the population standard deviation

n=40 sample size  

\mu_o =500 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Step1:State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 500, the system of hypothesis would be:  

Null hypothesis:\mu \leq 500  

Alternative hypothesis:\mu > 500  

Step 2: Calculate the statistic

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

We can replace in formula (1) the info given like this:  

z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90  

Step 3: Calculate the critical value

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

z_{crit}= 2.33

Step 4: Compare the statistic with the critical value

For this case we see that the calculated value is higher than the critical value

Step 5: Decision

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

Part 2

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>5.90)=1.82x10^{-9}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

7 0
3 years ago
Solve equation by using the quadratic formula.
adoni [48]
ANSWER IS C because I looked it up
3 0
3 years ago
What is the magnitude of -3 +4i?
Goshia [24]

Answer:

we have

-3+4i

let magnitude be |z|

|z|=\sqrt{( - 3) {}^{2}  + 4 {}^{2} }

|z|=5 unit

6 0
3 years ago
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