Question

Write the standard equation of a circle that passes through (−2, 10) with center (−2, 6).

Answer 1

The answer you’re looking for is B

Answer 2

Answer:

The answer to your question is the letter B.

Step-by-step explanation:

Data

Point = (-2, 10)

Center = (-2, 6)

Process

1.- Find the radius using the distance between two points

dCP = $\sqrt{(x2 - x1)^{2}+ (y2 - y1)^{2}}$

-Substitution

dCP = $\sqrt{(-2 + 2)^{2}+ (6 - 10)^{2}}$

dCP = $\sqrt{(0)^{2}+ (-4)^{2}}$

dCP = $\sqrt{16}$

dCP = 4

2.- Write the equation of the circle

Standard equation     (x - h)² + (y - k)² = r²

h = -2

k = 6

r = 4

                                       (x + 2)² + (y - 6)² = 4²

Equation                        (x + 2)² + (y - 6)² = 16