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Sholpan [36]
3 years ago
5

Write the standard equation of a circle that passes through (−2, 10) with center (−2, 6).

Mathematics
2 answers:
Levart [38]3 years ago
8 0
The answer you’re looking for is B
Korolek [52]3 years ago
4 0

Answer:

The answer to your question is the letter B.

Step-by-step explanation:

Data

Point = (-2, 10)

Center = (-2, 6)

Process

1.- Find the radius using the distance between two points

dCP = \sqrt{(x2 - x1)^{2}+ (y2 - y1)^{2}}

-Substitution

dCP = \sqrt{(-2 + 2)^{2}+ (6 - 10)^{2}}

dCP = \sqrt{(0)^{2}+ (-4)^{2}}

dCP = \sqrt{16}

dCP = 4

2.- Write the equation of the circle

Standard equation     (x - h)² + (y - k)² = r²

h = -2

k = 6

r = 4

                                       (x + 2)² + (y - 6)² = 4²

Equation                        (x + 2)² + (y - 6)² = 16

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