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Schach [20]
3 years ago
9

Carlos walked to school on 14 of the 20 school days in February. Which value is equivalent to the fraction of the school days in

February that Carlos walked to school?
Mathematics
1 answer:
Arturiano [62]3 years ago
6 0
Carlos walked 70% of times to school
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Landon scored an 85% on his test. If he got 34 problems correct, how many were on the test?
Sergeu [11.5K]

Answer:

There are 40 problems on the test

Step-by-step explanation:

Let p = the number of problems on the test

The number of problems on the test times the percent correct is the number correct

p * 85% = 34

p * .85 = 34

Divide each side by .85

p * .85/.85 = 34/.85

p = 40

There are 40 problems on the test

6 0
3 years ago
Help me and fast! And please show work!
tekilochka [14]

Answer:

171

Step-by-step explanation:

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6 0
3 years ago
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Find the x- and y- intercepts of the equation 7x+ 14 y=28
7nadin3 [17]

Chapter : Linear equations

Lesson : Math for Junior High School

7x + 14y = 28

if want to find x and y, we must substitution value 0 to the equation x and y :

# If x = 0, then :

7x + 14y = 28

= 7(0) + 14y = 28

= 0 + 14y = 28

= 14y = 28 → y = 28/14

= y = 2

# If y = 0, then :

7x + 14y = 28

= 7x + 14(0) = 28

= 7x + 0 = 28

= 7x = 28 → x = 28 / 7

= x = 4

and that result was proven x = 4 and y = 2

5 0
3 years ago
A couple does not wish to spend more than $60 for dinner at a restaurant. if a sales tax of 7% is added to the bill and they pla
Firlakuza [10]
Hey there!

The first step of this problem would be to add together our two percentages, then convert that percentage into a decimal by dividing by 100. 

15% + 7% = 22%

22 ÷ 100 = 0.22

It can be assumed here that 22% of the cost will be added tax and tip. We can use 0.22 to represent that percentage in our problem. Just multiply that decimal by the maximum amount of money they want to spend, $60, to get the amount that will just be tax and tip. Finally, subtract the tax and tip from $60 to find the most they can spend on the meal itself. 

60 × 0.22 = 13.20

60 – 13.20 = 46.80

The total amount they can spend is 46.80. 

Hope this helped you out! :-)
5 0
3 years ago
Suppose an airline policy states that all baggage must be box shaped with a sum of length, width, and height not exceeding 174 i
Leya [2.2K]

Answer:

The square-based box with the greatest volume under the condition that the sum of length, width, and heigth does not exceed 174 in is a cube with each edge of 58 in and a volume of 195112 in^{3}

Step-by-step explanation:

For this problem we have two constraints, that are as follows:

1) Sum of length, width, and heigth not exceeding 174 in

2) Lenght and width have the same measure (square-based box)

We know that volume is equal to the product of all three edges, and with the two conditions into account we have the next function:

V=(w^{2})(174-2w)\\V=174w^{2}-2w^{3}

The interval of interest of the objective function is [0, 87]

This problem requieres that we maximize the function that defines the volume. We start calculating the derivative of the function, wich is:

V'=348w-6w^{2} \\V'=(348-6w)(w)

We need to remember that the derivative of a function represents the slope of said function at a given point. The maximum value of the function will have a slope equal to zero.

So we find the value in wich the derivative equals zero:

0=(348-6w)(w)\\w_1=0\\w_2=348/6=58

The first value (w=0) will leave us with a 'height-only box', so the answer must be w=58 in

The value is between the interval of interest.

And, once we solve for the constraints, we have that:

Lenght = Width = Heigth = 58 in

Volume = 195112 in^{2}

8 0
3 years ago
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