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IrinaVladis [17]
2 years ago
7

Ben is 33 times as old as Daniel and is also 44 years older than Daniel. How old is Daniel?

Mathematics
1 answer:
EastWind [94]2 years ago
4 0

Answer:

x = 33·y

x = y + 44

x = 45.375 ∧ y = 1.375

Maybe the following question

Ben is 3 times as old as Daniel and is also 4 years older than Daniel. How old is Daniel?

x = 6 ∧ y = 2

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What is the Mean Average deviation from the Mean?<br> Numbers: 6, 2, 3, 3, 2, 2
Irina-Kira [14]

Answer:

2.42

Step-by-step explanation:

standard deviation= sqrt(variance)

Variance=E[X2] - E[X]2

E[X] = sum(X)/n=35/9, so E[X]2 = 1225/81

E[X2] =sum(X2)/n = 189/9 = 170/81

Variance= 476/81

Standard deviation = sqrt(476/81) ~2.42

6 0
2 years ago
Jamal has at most $100 to spend on computer paper and printer ink for his computer. He buys 1 box of paper for $24.99. If ink ca
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Answer:

1 box of paper with 3 ink cartridges

Step-by-step explanation:

$100 total

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7 0
3 years ago
PLEASE ANSWER
Olenka [21]

Answer:

x(1 - .4)

Step-by-step explanation:

x = regular price.

1 - .4 = .6 = 60%

The sale price is equal to the full price (aka x) minus the discounted price (40% of x = 40/100 times x =  .4x)

Therefore sale price = x - .4x or x(1 - .4)

4 0
3 years ago
Consider this expression. -4x to the second power 2x - 5 (1 + x) What expression is equivalent to the given expression? blank x
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6 0
2 years ago
For two events and , the probability that occurs is 0.8, the probability that occurs is 0.4, and the probability that both occur
sergey [27]

Answer:

P(B|A)=0.25  , P(A|B) =0.5

Step-by-step explanation:

The question provides the following data:

P(A)= 0.8

P(B)= 0.4

P(A∩B) = 0.2

Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.

To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:

P(B|A) = P(A∩B)/P(A)

      = (0.2) / (0.8)  

P(B|A)=0.25

To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:

P(A|B) = P(A∩B)/P(B)

          = (0.2)/(0.4)

P(A|B) =0.5

7 0
3 years ago
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